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Snezhnost [94]
3 years ago
12

A photograph measuring 4 inches wide and 5 inches long is enlarged to make a wall mural. If the mural is 82 inches wide, how lon

g is the mural?
help i will give points
Mathematics
1 answer:
Aliun [14]3 years ago
6 0
I say it around 150 inches that what I think
You might be interested in
He graph of the function f(x) = –(x + 6)(x + 2) is shown below.
Molodets [167]

The domain of the function is all real numbers, the range of a function is y ≤ 4

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have a function:

f(x) = –(x + 6)(x + 2)

If we plot this function on the coordinate plane, we will see it is a graph of a quadratic function.

Here the no other details are given.

But we can say:

  • The domain of the function is all real numbers.
  • The range of a function is y ≤ 4
  • The x-axis intercept will be at (-6, 0) and (-2, 0).

Thus, the domain of the function is all real numbers, the range of a function is y ≤ 4

Learn more about the function here:

brainly.com/question/5245372

#SPJ1

6 0
2 years ago
29×5/6 how do you solve it
frutty [35]
Is the whole thing divided by 6 or just the 5?
7 0
3 years ago
Read 2 more answers
(04.03 MC)
Vlad1618 [11]

Answer:

x = -2 and y = 3

{y = -3 x - 3, y = (3 x)/4 + 9/2} = x = -2 and y = 3

Step-by-step explanation:

Solve the following system:

{6 x + 2 y = -6

3 x - 4 y = -18

Express the system in matrix form:

(6 | 2

3 | -4)(x

y) = (-6

-18)

Solve the system with Cramer's rule:

x = -6 | 2

-18 | -4/6 | 2

3 | -4 and y = 6 | -6

3 | -18/6 | 2

3 | -4

Evaluate the determinant 6 | 2

3 | -4 = -30:

x = -6 | 2

-18 | -4/(-30) and y = 6 | -6

3 | -18/(-30)

Simplify -6 | 2

-18 | -4/(-30):

x = -1/30 -6 | 2

-18 | -4 and y = 6 | -6

3 | -18/(-30)

Simplify 6 | -6

3 | -18/(-30):

x = -(-6 | 2

-18 | -4)/30 and y = -1/30 6 | -6

3 | -18

Evaluate the determinant -6 | 2

-18 | -4 = 60:

x = (-1)/30×60 and y = -(6 | -6

3 | -18)/30

(-1)/30×60 = -2:

x = -2 and y = -(6 | -6

3 | -18)/30

Evaluate the determinant 6 | -6

3 | -18 = -90:

x = -2 and y = (-1)/30×-90

(-1)/30 (-90) = 3:

Answer: x = -2 and y = 3

___________________________________________

Solve the following system:

{y = -3 x - 3

y = (3 x)/4 + 9/2

Express the system in standard form:

{3 x + y = -3

-(3 x)/4 + y = 9/2

Express the system in matrix form:

(3 | 1

-3/4 | 1)(x

y) = (-3

9/2)

Write the system in augmented matrix form and use Gaussian elimination:

(3 | 1 | -3

-3/4 | 1 | 9/2)

Add 1/4 × (row 1) to row 2:

(3 | 1 | -3

0 | 5/4 | 15/4)

Multiply row 2 by 4/5:

(3 | 1 | -3

0 | 1 | 3)

Subtract row 2 from row 1:

(3 | 0 | -6

0 | 1 | 3)

Divide row 1 by 3:

(1 | 0 | -2

0 | 1 | 3)

Collect results:

Answer:  {x = -2 , y = 3

5 0
3 years ago
Find a direct relationship between x and y.<br> x = 3t and y = 2t + 7
ikadub [295]

Answer:

y = \frac{2}{3} x + 7

Step-by-step explanation:

Given

x = 3t ( divide both sides by 3 )

\frac{1}{3} x = t

Substitute this value into y = 2t + 7

y = 2 × \frac{1}{3} x + 7 = \frac{2}{3} x + 7

6 0
3 years ago
The electric potential in a circuit is given by
shtirl [24]
We are given with the equationL
V(t) = 320 e^(-3.1t)
At V = 200
200 = 320 e^(-3.1t)
t = 0.15 s

100 = 320 e^(-3.1t)
t = 0.36 s

It takes 0.36 - 0.15 = 0.21 s for the voltage to drop from 200 to 100 volts.
3 0
3 years ago
Read 2 more answers
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