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Fofino [41]
3 years ago
12

(-3).(+9)-(-24)-(+6).(+2)

Mathematics
1 answer:
Xelga [282]3 years ago
5 0
The answer is -15 if you want it solved
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Evaluate the expression below when x= -2 x+4
ZanzabumX [31]

Answer:

x+4= -2+4

x+4 = 2

Step-by-step explanation:

3 0
3 years ago
The point(5/13,Y) IS IN THE 4TH quadrant corresponds to angle on the unit circle
shutvik [7]
4th quadrant is positive x (cos) and negative y (sin)

Use the Pythagorean Theorem to calculate the value of y (sin).
x² + y² = c²
5² + y² = 13²
25 + y² = 169
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Since the y-value is negative in the 4th quadrant, then y = -12
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Help! Isosceles, scalene or equilateral
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equilateral

Step-by-step explanation:

all of the side lengths are the same along with the angles

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Please help! this is a final! FUNCTIONS
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The zeroes are -1/2 and -2
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3 years ago
A circus tent is cylindrical upto a height of 3.3 m and conical above it if the diameter of the base is 100m and slant height of
Rina8888 [55]

Total cost of canvas required in making the tent is rupees 79128

<em><u>Solution: </u></em>

Given:

Height of the cylindrical tent = h = 3.3 m

Diameter of it's base = d = 100m

radius = \frac{diameter}{2} = \frac{100}{2} = 50

r = 50 m

<em><u>Curved surface area of cylinder:</u></em>

C.S.A = 2 \pi rh

C.S.A = 2 \times 3.14 \times 50 \times 3.3 = 1036.2

Thus Curved surface area of cylinder = 1036.2 square meter

<em><u>Curved surface area of cone:</u></em>

C.S.A = \pi rl

C.S.A = 3.14 \times 50 \times 56.4 = 8854.8

Thus Curved surface area of cone = 8854.8 square meter

<em><u>Total curved area of tent:</u></em>

⇒ curved area of cone + curved area of cylinder

\rightarrow 8854.8 + 1036.2=9891

Thus total curved area of tent = 9891 square meter

<em><u>find total cost of canvas required in making the tent:</u></em>

The cost of canvas is 8 rupees per square meter

\rightarrow \text{total cost } = 9891 \times 8 = 79128

Thus total cost of canvas required in making the tent is rupees 79128

7 0
3 years ago
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