Question

In how many ways can people be lined up to get on a bus if a particular person always boards the bus first or last?

Answer 1

Incomplete question. I Assumed the number of people is 6. In other words, In how many ways can 6 people be lined up to get on a bus if a particular person always boards the bus first or last?

Answer:

6

Step-by-step explanation:

Note, this question involves the use of the permutation formula; which helps determine the arrangement or rearrangement of a set of objects in an ordered way. Since we are told a particular person (ie 1 person) from among the group always boards first or last, it forms our r.

P(n,r)= $\frac{n!}{(n-r)!}$ where n = number of people; r = the difference taken at a time.

P(n,r) = $\frac{6!}{(6-1)!}$ = $\frac{720}{120} = 6$