CH2O3
C=19.36\12 = 1.61
H=3.25\1.008 =3.22
O=77.39\16=4.83
then dived the moles with the smallest mole
C=1.61\1.61=1
H=3.22\1.61=2
O=4.83\1.61=3
E.F
CH2O3
It’s earthquakes
hope that helps
Answer:
10. F
11. A
12. B
13. C
14. G
15. A
16. F
17. B
18. D
19. E
20. B
Explanation:
im sorry
ik some are probably incorrect
Based on the table and the equation of reaction; the
- rate of consumption of oxygen between time 20 and 40s is 0.005 M/s
- rate of consumption of oxygen between time 40 and 60s is 0.0025 M/s
<h3>What is rate of a reaction?</h3>
The rate of a reaction is the rate at which reactants molecules are consumed or products are formed.
- Rate of reaction = change in concentration of reactants or products/ time taken
Based on the equation of reaction, the rate of consumption of oxygen is equal to the rate of consumption of methane.
Thus. rate of consumption of oxygen from time 20 seconds to time 60 seconds is calculated as follows:
Rate between 20 and 40 = 1.0 - 0.9/20
- Rate of consumption of oxygen = 0.005 M/s
Rate between 40 and 60 = 0.9 - 0.85/20
- Rate of consumption of oxygen = 0.0025 M/s
Therefore, the rate of consumption of oxygen decreases with time.
Learn more about rate of reaction at: brainly.com/question/25724512
The standard cell potential of a cell made of theoretical metals ma/ma2+ and mb/mb2+ is to be determined. We are given their reduction potentials:
-0.19 v for A
-0.85 v for B
To solve for the standard cell potential, examine the reaction and
the standard cell potential for this case is (-0.19- (-0.85)) v = -0.66 v<span />
