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brilliants [131]
3 years ago
5

Time (sec) [CH4] (mol/L)

Chemistry
1 answer:
Oxana [17]3 years ago
8 0

Based on the table and the equation of reaction; the

  • rate of consumption of oxygen between time 20 and 40s is 0.005 M/s
  • rate of consumption of oxygen between time 40 and 60s is 0.0025 M/s

<h3>What is rate of a reaction?</h3>

The rate of a reaction is the rate at which reactants molecules are consumed or products are formed.

  • Rate of reaction = change in concentration of reactants or products/ time taken

Based on the equation of reaction, the rate of consumption of oxygen is equal to the rate of consumption of methane.

Thus. rate of consumption of oxygen from time 20 seconds to time 60 seconds is calculated as follows:

Rate between 20 and 40 = 1.0 - 0.9/20

  • Rate of consumption of oxygen = 0.005 M/s

Rate between 40 and 60 = 0.9 - 0.85/20

  • Rate of consumption of oxygen = 0.0025 M/s

Therefore, the rate of consumption of oxygen decreases with time.

Learn more about rate of reaction at: brainly.com/question/25724512

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<span>Some examples of atoms that have special electronic configurations are copper and chromium. For example, copper is more stable when the 3d subshell is completely filled. This leaves the 4s subshell with only 1 electron. Chromium is also more stable when its s and d subshells are only half full. The orbital notation depicts these special cases, whereas the dot structure does not.</span>
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