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bekas [8.4K]
2 years ago
10

What is the greatest number of relative maximum that a polynomial of degree 15 can have?

Mathematics
1 answer:
alisha [4.7K]2 years ago
4 0

Answer:

i dont know

Step-by-step explanation:

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Please help please ​
jarptica [38.1K]

Answer:

1.) supplementary  m<1+m<2=180 and m<2+m<3=180

2.) congruent, supplementary

Step-by-step explanation:

the answers are in this order above

5 0
3 years ago
Can someone please help me with these 2 questions?
Aleonysh [2.5K]

Answer:

1. The correct answer is graph b

2. the correct answer is t>100

Step-by-step explanation:


5 0
3 years ago
Please answer correctly! I will mark you Brainliest! The pictures go together! Please No answering without knowing answer or sca
Anna007 [38]

Answer:

904.32

Step-by-step explanation:

\frac{4}{3}\cdot \:3.14\cdot \:6^3=904.32

The volume of a sphere is \frac{4}{3}\pir^{3}

6 0
3 years ago
I need help asap. Evaluate Expressions
Anit [1.1K]

Answer:

1:

p-r/6=-6-(-6)/6=-6+1=<u>-</u><u>5</u>

<u>2</u><u>:</u>

<u>p-</u><u>(</u><u>m-n</u><u>)</u><u>=</u> -1-(-4-4)=-1-(-8)=-1+8=<u>7</u>

3:

(z+y)/2)3=(-5-4)/3=-9/3=<u>-</u><u>3</u>

<u>4</u><u>:</u>

m/6-n=6/6-6=1-6=<u>-</u><u>5</u>

5:

k³-h=3³-(-2)=27+2=<u>2</u><u>9</u>

6:

p-(p-(m-3))=5-(5-(4-3))=5-(5-1)=5-4=<u>1</u>

7:

(k)(k-j)+3=(5)(5-5)+3=5*0+3=<u>3</u>

8.

p²/6-q=6²/6-4=6-4=<u>2</u>

<u>9</u><u>;</u>

zx+3³=6*4+3³=24+27=<u>5</u><u>1</u><u>.</u>

<u>1</u><u>0</u><u>:</u>

<u>y</u><u>+</u><u>z</u><u>-</u><u>(</u><u>y</u><u>-</u><u>x</u><u>)</u><u>=</u>5+4-(5-2)=9-3=<u>6</u>

<u>S</u><u>o</u><u>m</u><u>e</u><u> </u><u>b</u><u>a</u><u>s</u><u>i</u><u>c</u><u> </u><u>r</u><u>u</u><u>l</u><u>e</u><u>s</u><u>:</u>

+. +. +=+

+. * +=+

+. ÷ +=+

+. - +=+

and

+. +. -=add and put sigh of greater one.

-. * +=-sigh

-÷-=+sigh

- - -=add and put - sigh

7 0
3 years ago
Read 2 more answers
Your 3 nieces and 3 nephews (6 children total) are visiting for the holidays. You must give them each a present. They all love l
marusya05 [52]

Answer:

The 6 Lego kits can be selected from the 9 available Lego kits in 84 ways.

Step-by-step explanation:

Use combinations to solve this problem.

Combination is defined as the selection of <em>r</em> elements from <em>n</em> distinct objects irrespective of the order. The objects cannot be replaced.

There are 9 Lego kits available.

And the total number of children is 6.

That is, we need to select 6 Lego kits from the 9 available Lego kits.

6 Lego kits can be selected from the 9 available Lego kits in 9\choose 6 ways.

Solving the combination as follows:

{9\choose 6}=\frac{9!}{6!\times(9-6)!} \\=\frac{362880}{720\times6}\\ =84

Thus, there are 84 ways to select 6 Lego kits from 9 available Lego kits.

4 0
3 years ago
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