Answer:
D. 2058.24 in³
Step-by-step explanation:
Let r,h be the radius and height of smaller can and R,H be the radius and height of larger can
Then, R=4r and H=4h
Volume of smaller can=32.16 in³
⇒ πr²h=32.16 in³
Volume of larger can= πR²H
= π(4r²)×4h
= 64πr²h
= 64×32.16 in³
= 2058.24 in³
Hence, correct option is:
D. 2058.24 in³
I believe the answer is 24 if not im sorry
0 solutions because simplifying the equation gives us 1 = 5, which is never true
Answer:
D. 14x - 4
Step-by-step explanation:
P = 2(L + W)
P = 2(4x + 5 + 3x - 7)
P = 2(7x - 2)
P = 14x - 4
