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3 years ago

Represent each of the following units as a combination of primitive

Engineering

1 answer:

zimovet [89]3 years ago

3 0

Answer:

a. unit of length: [L]

b. unit of volume: [ $L^3$ ]

c. unit of pressure: $P=\frac{F}{A} \equiv\frac{[MLT^{-2}]}{[L^2]}$ $[ML^{-1}T^{-2}]$

d. unit of power: $N.m.s^{-1}\equiv [ML^2T^{-3}]$

e. unit of force: $[kg.m/s^2]\equiv [MLT^{-2}]$

f. unit of power: $N.m.s^{-1}\equiv [ML^2T^{-3}]$

Force: $F=m.a=m.\frac{v}{t}=m.\frac{x}{t}\div t$

Power: $P=\frac{W}{t}=\frac{F.x}{t}$

where:

F = force

A = area

W = work

t = time

a = acceleration

v = velocity

x = displacement

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A rigid canister with a radius of 5 in and a height of 10 in is filled with air. The initial pressure and temperature of air in

Elza [17]

Answer:1.458 Btu

Explanation:

Given

radius of canister $\left ( r\right )=5in$

Height of canister $\left ( h\right )=10 in.$

Initial pressure $\left ( P_i\right )=14.7 Psi$

Initia ltemprature $\left ( T_i\right )=70^{\circ}F$

Final pressure $\left ( P_f\right )=30Psi$

as canister is rigid therefore change in volume is zero

therefore

$\frac{P_i}{T_i}$ = $\frac{P_f}{T_f}$

$\frac{14.7}{70}$ = $\frac{30}{T_f}$

$T_f=142.85^{\circ}F$

volume of canister= $\pi \times r^{2}\times h$

= $\pi \times 5^{2}\times 10=250\pi$

volume of canister=12872,038.8 $mm^3$

now calculating mass of air

PV=mRT

substituting values

$\left ( 14.7Psi\right )\left ( 12872,038.8 mm^3\right )=m\left ( 0.287\right )\left ( 70^{\circ}F\right )$

m=21.0192 gm

Therefore heat transferred = $mc_p\left ( T_f-T_i\right )$

= $21.0192\times 10^{-3}\times \left ( 142.857-70\right )$

=1539.052J=1.458Btu

3 0

4 years ago

A) Fix any errors to get the following program to run in your environment. B) Document each line of code with comments and descr

Bingel [31]

Answer:

Answer is explained below

Explanation:

Part A -:

Error statement -:

prog.cpp: In function ‘void p(const int*, int)’:

prog.cpp:7:15: error: assignment of read-only location ‘* list’

list[0] = 100;

There is one error in the code in following part

void p( const int list[], int arraySize)

{

list[0] = 100;

}

you are passing list as constant but changing it inside the function that is not allowed. if you pass any argument as const then you can't change it inside the function. so remove const from function argument solve the error.

Part B -:

change made

void p( int list[], int arraySize)

{

list[0] = 100;

}

Executable fully commented code -: 

#include <iostream> // importing the iostream library

using namespace std;

void m(int, int []); // Function declearation of m

void p( int list[], int arraySize) // definition of Function p

{

list[0] = 100; // making value of first element of list as 100

}

int main()

{

int x = 1; // initilizing x with 1

int y[10]; // y is a array of 10 elements

y[0] = 1; // first element of y array is 1

m(x, y); // call m function

// printing the desired result

cout << "x is " << x << endl;

cout << "y[0] is " << y[0] << endl;

return 0;

}

void m(int number, int numbers[]) // Function definition of m

{

number = 1001; // value of number is 1001 locally

numbers[0] = 5555; // making value of first element of numbers array 5555

}

Part C :-

In program we initilize x with value 1 and create an array y of 10 elements.

we initilize the y[0] with 1\

then we call function m. In function m ,first argument is value of x and second argument is the pointer to the first element of array y.

so value of x is changed locally in function m and change is not reflected in main function.

but value of y[0] is changed to 5555 because of pass by refrence.

So we are getting the following result :-

x is 1

y[0] is 5555

4 0

3 years ago

Select the correct answer from each drop-down menu.

Maurinko [17]

Answer:

Migration and indoor planting if too much rain outside.

Explanation:

If rain is a problem, migrating to another place is an option. If you can't leave your place, then I suggest planting inside. (No list was given)

5 0

4 years ago

Technician A says that excessive end play causes rapid wear of the sealing rings and possibly the sealing ring groove. Technicia

DerKrebs [107]

Answer:

Technician A only

Explanation:

Rapid wear of the sealing ring and the seal ring groove are result of excessive end play

7 0

3 years ago

The human eye, as well as the light-sensitive chemicals on color photographic film, respond differently to light sources with di

jeka57 [31]

Answer:

a) at T = 5800 k

band emission = 0.2261

at T = 2900 k

band emission = 0.0442

b) daylight (d) = 0.50 μm

Incandescent ( i ) = 1 μm

Explanation:

To Calculate the band emission fractions we will apply the Wien's displacement Law

The ban emission fraction in spectral range λ1 to λ2 at a blackbody temperature T can be expressed as

F ( λ1 - λ2, T ) = F( 0 ----> λ2,T) - F( 0 ----> λ1,T )

Values are gotten from the table named: blackbody radiation functions

a) Calculate the band emission fractions for the visible region

at T = 5800 k

band emission = 0.2261

at T = 2900 k

band emission = 0.0442

attached below is a detailed solution to the problem

b)calculate wavelength corresponding to the maximum spectral intensity

For daylight ( d ) = 2898 μm *k / 5800 k = 0.50 μm

For Incandescent ( i ) = 2898 μm *k / 2900 k = 1 μm

3 0

3 years ago