1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Naddika [18.5K]
3 years ago
9

2. In the above figure, what type of cylinder arrangement is shown in the figure above?

Engineering
1 answer:
Oduvanchick [21]3 years ago
5 0

Answer:

C. Horizontal

Explanation:

The type of cylinder arrangement that is shown in the figure is "Horizontal"

The arrangement is actually horizontal which is known to be horizontally opposed engine. Such engine is known as flat engine. It's a piston engine that has the cylinders located on either side of a crankshaft. It is usually located at the central crankshaft. This type of engine has performance advantage over others.

You might be interested in
Write a C program that asks the user to enter two numbers, obtains the two numbers from the user and prints the sum, product, di
Bogdan [553]

Answer:

View Image

Explanation:

Initialize your variable as a float or double since you're going to be using fractions in your answer.

User scanf() to get user input.

Print out the sum, product, quotient, and difference between the two numbers.

8 0
3 years ago
Kerosene flows through 3/4 standard type K drawn copper tube. The pressure drop measured at two points 50 m apart is 130 kPa. De
Anettt [7]

Answer:

Q=4.98\times 10^{-3}\ m^3/s

Explanation:

Given that

L= 50 m

Pressure drop = 130 KPa

For Copper tube is 3/4 standard type K drawn tube

Outside diameter=22.22 mm

Inside diameter=18.92 mm

Dynamic viscosity for kerosene

\mu =0.00164\ Pa.s

Pressure difference given as

\Delta P=\dfrac{128\mu QL}{\pi d_i^4}

Where

L is length of tube

μ is dynamic viscosity

Q is volume flow rate

d is inner diameter of tube

ΔP is pressure drop

Now by putting the values

\Delta P=\dfrac{128\mu QL}{\pi d_i^4}

130\times 1000=\dfrac{128\times 0.00164\times 50\times Q}{\pi\times 0.0189^4}

Q=4.98\times 10^{-3}\ m^3/s

So flow rate is Q=4.98\times 10^{-3}\ m^3/s

7 0
3 years ago
A car moves along a circular track of radius 250 ft such that its seed for a short period of time 0<_ t <_ 4s, is v = 3(t
beks73 [17]

Answer: a) -5 ft/s²

B) 4.5 ft

Explanation: Radius= 250ft

Velocity V = 3(t-t²)ft/s

A). When t= 3 s, the acceleration is

dv/dt = 1-2t

dv/dt = 1- 2(3)

= 1-6

= -5 ft/s²

B. How far it traveled in 3 sec

Distance= 3t²/2 -t³/3 ft

Substituting 3

Distance = 27/2 - 9

= 13.5 - 9

= 4.5 ft

7 0
3 years ago
A dryer is shaped like a long semi-cylindrical duct of diameter 1.5 m. The base of the dryer is occupied with water-soaked mater
Anestetic [448]

Answer:

0.0371 kg/s.m

Explanation:

From the given information, let's have an imaginative view of the semi-cylinder; (The image is shown below)

Assuming the base surface of both ends of the cylinder is denoted by:

A_1  \ and   \ A_2

Thus, using the summation rule, the view factor F_{11 and F_{12 is as follows:

F_{11}+F_{12}=1

Let assume the surface (1) is flat, the F_{11} = 0

Now:

0+F_{12}=1

F_{12}=1

However, using the reciprocity rule to determine the view factor from the dome-shaped cylinder A_2 to the flat base surface A_1; we have:

A_2F_{21} = A_{1}F_{12} \\ \\ F_{21} = \dfrac{A_1}{A_2}F_{12}

Suppose, we replace DL for A_1 and

A_2 =  \dfrac{\pi D}{2}

Then:

F_{21} = \dfrac{DL}{(\dfrac{\pi D}{2}) L} \times 1 \\ \\  =\dfrac{2}{\pi} \\ \\  =0.64

Now, we need to employ the use of energy balance formula to the dryer.

i.e.

Q_{21} = Q_{evaporation}

But, before that;  let's find the radian heat exchange occurring among the dome and the flat base surface:

Q_{21}= F_{21} A_2 \sigma (T_2^4-T_1^4) \\ \\ Q_{21} = F_{21} \times \dfrac{\pi D}{2} \sigma (T_2^4 -T_1^4)

where;

\sigma = Stefan \ Boltzmann's \ constant

T_1 = base \ temperature

T_2 = temperature  \ of  \ the  \ dome

∴

Q_{21} = 0.64 \times (\dfrac{\pi}{2}\times 1.5) \times 5.67 \times 10^4 \times (1000^4 -370^4)\\ \\ Q_{21} = 83899.15 \ W/m

Recall the energy balance formula;

Q_{21} = Q_{evaporation}

where;

Q_{evaporation} = mh_{fg}

here;

h_{fg} = enthalpy of vaporization

m = the water mass flow rate

∴

83899.15 = m \times 2257 \times 10^3  \\ \\  m = \dfrac{83899.15}{ 2257 \times 10^3 }\\ \\ \mathbf{m = 0.0371 \ kg/s.m}

6 0
2 years ago
¿Qué aspecto importante debemos conocer en el ámbito del
german
I would help but don’t speak that sorry
8 0
2 years ago
Other questions:
  • Which statement most accurately describes Pascal's law?
    12·2 answers
  • Write a modular program that finds the equation, area, and circumference of a circle, given the coordinates of the center of the
    11·1 answer
  • Air within a piston cylinder assembly executes a Carnot refrigeration cycle between hot and cold reservoirs at TH=600 K and TC=3
    13·1 answer
  • A copper-nickel alloy of composition 60 wt% Ni-40 wt% Cu is slowly heated from a temperature of 1250°C (2280 °F). (a) At what te
    9·1 answer
  • A flow rate sensing device used on a liquid transport pipeline functions as follows. The device provides a 5-bit output where al
    7·1 answer
  • Calculate pressure at the mid-plane of an annular cylinder of iron powder pressed using double-action press. The punch pressure
    12·1 answer
  • The coolant heat storage system:
    10·1 answer
  • what do you expect the future trends of an operating system in terms of (a) cost (b) size (c) multitasking (d) portability (e) s
    12·1 answer
  • What is the hardest part of engineering?
    12·1 answer
  • Which option distinguishes why the behaviors of the team in the following scenario are so important during the engineering desig
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!