Answer:
Step-by-step explanation:
∛-64 = -4
![\sqrt[3]{m^{15}} =m^5](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bm%5E%7B15%7D%7D%20%3Dm%5E5)
∛n³ = <em>n</em>
Answer:
(x -2) (x- 8) (x+7)
Step-by-step explanation:
So you'd have to convert all of the values to one form, and I find it easiest to do it in decimals. 61% would be 0.61, 0.605 stays the same, 3/5 would be 0.6, and 59% would be 0.59. Now you can order them:
0.59, 0.6, 0.605, 0.61
You have to convert them back to their original form, however, so your answer would be
59%, 3/5, 0.605, 61%
I hope this helps!
Answer:
9
Step-by-step explanation:
To find the area of a triangle where you know the x and y coordinates of the three vertices, you'll need to use the coordinate geometry formula: area = the absolute value of Ax(By - Cy) + Bx(Cy - Ay) + Cx(Ay - By) divided by 2. Ax and Ay are the x and y coordinates for the vertex of A. The same applies for the x and y notations of the B and C vertices.
Fill in the numbers for each corresponding letter combination within the formula.
Fill in your formula like this: 0(8-10) + 3(0-0) + 9(0-8).
Subtract the numbers within the parentheses.
0 from 8 = 8, 0 from 0 = 0 and 8 from 10 = 2.
Multiply that result by the number to the left of the parentheses.
0 by 8 = 0, 3 by 0 = 0 and 9 by 2 = 18.
Add the three products together.
0 + 0 + 18 = 18
Divide the sum of the three products by 2.
18 ÷ 2 = 9
9/27, 12/27, 16/27
So this is a geometric sequence as each term is 4/3 the previous term.
Since the common ration is greater than one the sum of the series diverges, it does not exist. (The sum just keeps getting larger and larger)
For a geometric series to have a sum r^2<1
So that the normal sum....
s(n)=a(1-r^n)/(1-r) becomes if r^2<1
s=a/(1-r)
