Ask question

Ask question

All categories

3 years ago

10

Assume that after t hours on the job, a factory worker can produce 100te^-.5t units per hour. How many units does the worker pro

duce during the first three hours?

1 answer:

VMariaS [17]3 years ago

5 0

The number of units produced by the worker during t hours of work can be modelled by the following function:

$N(t)=100t e^{(-0.5t)}$

To find the number of units produced during first 3 hours, we can substitute 3 for t. This will give us the number of units produced by the worker during first 3 hours.

$N(3)=100(3) e^{-0.5(3)} = 67$

Thus the worker will produce 67 units during the first 3 hours of the work.

You might be interested in

I forgot how to do these problems can you help me

Galina-37 [17]

Answer:

s is equal to 2

Step-by-step explanation:

3 0

3 years ago

The length of AC⎯⎯⎯⎯⎯ is 10 inches.

Maru [420]

Answer:

5 in

Step-by-step explanation:

AC = the diameter

FA = the radius

diameter=2*radius

10=2*FA

FA=10/2

FA=5 in

3 0

2 years ago

Read 2 more answers

Find all the zeroes of the equation(with simple steps).

uysha [10]

<u>Answer-</u>

<em>The zeros are, $5,\ -5,\ 4i,\ -4i$ </em>

<u>Solution-</u>

$\Rightarrow -3x^4+27x^2+1200=0$

$\Rightarrow -3(x^2)^2+27(x^2)+1200=0$

Here,

a = -3, b = 27, c = 1200

So,

$x^2=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

$=\dfrac{-27\pm \sqrt{-27^2-4\cdot (-3)\cdot 1200}}{2\cdot (-3)}$

$=\dfrac{-27\pm \sqrt{729+14400}}{-6}$

$=\dfrac{-27\pm 123}{-6}$

$=\dfrac{-27+123}{-6},\ \dfrac{-27- 123}{-6}$

$=\dfrac{96}{-6},\ \dfrac{-150}{-6}$

$=-16,\ 25$

So,

$\Rightarrow x^2=25,\ -16$

$\Rightarrow x=\sqrt{25},\ \sqrt{-16}$

$\Rightarrow x=5,\ -5,\ 4i,\ -4i$

8 0

2 years ago

PLZ HELP!!! Will mark brainliest if answers are correct. I'm being timed I need answer as soon as possible. Also willl give a th

Ket [755]

Answer:

Order Data (least to greatest): 35,40,42,46,47,52

Mean: 43.66

MAD:4.66

Could not figure out Mean of Differences sorry!

Step-by-step explanation:

To find the mean you add all of the numbers and divide by the amount.

To find MAD find the sum of the data values, and divide the sum by the number of data values.

5 0

3 years ago

The head librarian at the Library of Congress has asked her assistant for an interval estimate of the mean number of books check

Verdich [7]

Answer:

$n=(\frac{1.960(150)}{90})^2 =10.67 \approx 11$

So the answer for this case would be n=11 rounded up to the nearest integer

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma =150$ represent the population standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The confidence interval for this case is given by: (740, 920)

We can find the estimate for the mean and we got:

$\bar X = \frac{740+920}{2} = 830$

and the margin of error is given by :

$ME = \frac{920-740}{2}= 90$

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$ (a)

And on this case we have that ME =90 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} s}{ME})^2$ (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got $z_{\alpha/2}=1.960$ , replacing into formula (b) we got:

$n=(\frac{1.960(150)}{90})^2 =10.67 \approx 11$

So the answer for this case would be n=11 rounded up to the nearest integer

5 0

2 years ago