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3 years ago

2) How could a motorcycle (a vehicle with less mass) make a van (a

Physics

1 answer:

jeyben [28]3 years ago

8 0

it depends upon what state they are in like in motion or res

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Which shows evidence of active transport?

Sunny_sXe [5.5K]

Answer: D

X and Y

Explanation:

X The least amount of magnesium Took in magnesium

Y Slightly less magnesium than the cell Took in magnesium

Because active transport occurs when ions or molecules move from less concentration region to high concentration region through semi membrane with the help of some energy.

5 0

3 years ago

Read 2 more answers

In number one is Mirna is pregnant and must consult a medical professional, What kind of doctor should she seek?

Nitella [24]

I think a obstetrician, since they specifically deal with pregnancy and birth. They would guide you through the entire pregnancy. Hope this helps :))

5 0

3 years ago

What if someone refers to a crystal's " habit" what are they referring to?

Alenkinab [10]

It's the external shape of the crystal. You can determine how developed the crystals are and it'll help identify what species of mineral it is. Hope that helped

7 0

3 years ago

Two vectors A and B have components (0,1) and (-1,3), respectively. What is magnitude of the sum of these two vectors?

AnnZ [28]

We first add the x and y components of the vector to get the x and y components of the resultant vector:
(0 - 1, 1 + 3)
-1 , 4
magnitude = √(1² + 4²)
magnitude = 4.12
The answer is B

4 0

3 years ago

White light (400–700 nm) is incident on a 600 line/mm diffraction grating. What is the width of the first-order rainbow on a scr

Tema [17]

Answer:

Δy=0.431m

Explanation:

Diffraction grating with split space d,to find the fringe position ym,we must to find the angle from

dSinα=mλ

A grating with N slits or lines per mm has slit spacing of

d=1/N

d=(1/600mm)

d=1.67×10⁻³mm

For 400nm wavelength:

α=Sin⁻¹(mλ/d)

$\alpha =Sin^{-1}(\frac{400*10^{-9} }{1.67*10^{-6}} )\\ \alpha =13.910^{o}$

And the position of first order lowest wavelength fringe on the screen is:

$y_{1}=Ltan\alpha_{1}\\y_{1}=2tan(13.910)\\ y_{1}=0.49445m$

For 700nm wavelength:

α=Sin⁻¹(mλ/d)

$\alpha =Sin^{-1}(\frac{700*10^{-9} }{1.67*10^{-6}} )\\ \alpha_{2} =24.83^{o}$

And the position of first order highest wavelength fringe on the screen is:

$y_{2}=Ltan\alpha_{2}\\y_{2}=2tan(24.83)\\ y_{2}=0.925595m$

The difference between the first order lowest and highest wavelength fringe is

Δy=(0.925595 - 0.49445)m

Δy=0.431m

6 0

3 years ago