Answer: 2.4×10^-3 v/m
Explanation: distance between plates of capacitor (d) =5.0×10^-3m
Potential difference between plates (v) = 12v
Force on electronic charge (f) = 3.8×10^-16 N
Strength of electric field (E) =?
The formulae that relates potential difference, eoectiic field strength and distance between plates is given as
v = Ed
By substituting the parameters, we have that
12 = E × 5.0×10^-3
E = 12/ 5.0 × 10^-3
E = 2.4×10^-3 v/m
Answer:
180 Newton(N)
Explanation:
force =mass *acceleration
=60 * 3
=180 kgm/s^2
=180 N
Answer:
n = 756.25 giga electrons
Explanation:
It is given that,
If the charge on the negative plate of the capacitor, 
Let n is the number of excess electrons are on that plate. Using the quantization of charges, the total charge on the negative plate is given by :

e is the charge on electron

or
n = 756.25 giga electrons
So, there are 756.25 giga electrons are on the plate. Hence, this is the required solution.
Answer:
The SI unit of length verified globally is meters(m)
Answer:
due to the magnetic field
Explanation:
magnetic field is the same in the vacuum