Answer: Width would become 21 and length would become 33. Original perimeter is 100, increased perimeter is 108 which is a 7.69% increase
Answer:
2x² + 3x + 4 + (17x + 9) / (x² − 4)
Step-by-step explanation:
Start by setting up the division. Make sure to write all the coefficients, even the zero ones.
x² + 0x − 4 | 2x⁴ + 3x³ − 4x² + 5x − 7
Start by dividing the first term of the dividend (2x⁴) by the first term of the divisor (x²). That's 2x²; it'll be the first term in quotient. Multiply the divisor by 2x²:
2x⁴ + 0x³ − 8x²
Subtract that from the first three terms of the dividend:
3x³ + 4x²
Drop down the next term from the dividend, and start the process all over again.
3x³ + 4x² + 5x
When you finish, the quotient will be 2x² + 3x + 4, and the remainder will be 17x + 9.
Answer:
The base is 19.5.
Step-by-step explanation:
The given question is, "The perimeter of a rectangle is 58 and its base exceeds its width by 10, how long is the base?"
Perimeter = 58
Base, l = 10+b
The perimeter of a rectangle is :
P = 2(l+b)
58 = 2(10+b+b)
29 = (10+2b)
29-10 = 2b
19 = 2b
b = 9.5
Base, l = 10 + 9.5
= 19.5
Hence, the base is 19.5.
A. the polynomial can then be factored to (x+10)(x+2).