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katen-ka-za [31]
3 years ago
10

Which is greater, 0.6 or 0.60?

Mathematics
2 answers:
artcher [175]3 years ago
5 0
None of them because they are the same
fgiga [73]3 years ago
5 0
They are equal because if you add a zero to 0.6 it will be the same
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7.Show that quadrilateral FGHJ is a trapezoid, but is not a parallelogram.
Fantom [35]

Answer:

Line FJ is -3/1, while Line GH is 3/-2

Step-by-step explanation:

6 0
2 years ago
What is three-fourths of 1,968
lara31 [8.8K]
All you have to so is divide 1968 by 4.

1968 ÷ 4 = 496.5 = 1/4


Now multiply 496.5 by 3 =  1, 489.5 = 3/4


I hope this helps! :_
7 0
2 years ago
Read 2 more answers
A baker makes apple tarts and apple pies each day. Each tart, t, requires 1 apple, and each pie, p, requires 8 apples. The baker
Lynna [10]
For this case, the first thing we must do is define variables.
 We have then:
 t: number of tarts
 p: number of pies
 We now write the system of equations:
 Each tart, t, requires 1 apple, and each pie, p, requires 8 apples. The baker receives a shipment of 184 apples every day:
 8p + t ≤ 184
 the baker makes no more than 40 tarts per day:
 t ≤ 40
 Answer:
 A system of inequalities that can be used to find the possible number of pies and tarts the baker can make is:
 D. t ≤ 40
 8p + t ≤ 184
5 0
3 years ago
Read 2 more answers
Find the general solution of the differential equation and check the result by differentiation. (Use C for the constant of integ
atroni [7]

Answer: y=Ce^(^3^t^{^9}^)

Step-by-step explanation:

Beginning with the first differential equation:

\frac{dy}{dt} =27t^8y

This differential equation is denoted as a separable differential equation due to us having the ability to separate the variables. Divide both sides by 'y' to get:

\frac{1}{y} \frac{dy}{dt} =27t^8

Multiply both sides by 'dt' to get:

\frac{1}{y}dy =27t^8dt

Integrate both sides. Both sides will produce an integration constant, but I will merge them together into a single integration constant on the right side:

\int\limits {\frac{1}{y} } \, dy=\int\limits {27t^8} \, dt

ln(y)=27(\frac{1}{9} t^9)+C

ln(y)=3t^9+C

We want to cancel the natural log in order to isolate our function 'y'. We can do this by using 'e' since it is the inverse of the natural log:

e^l^n^(^y^)=e^(^3^t^{^9} ^+^C^)

y=e^(^3^t^{^9} ^+^C^)

We can take out the 'C' of the exponential using a rule of exponents. Addition in an exponent can be broken up into a product of their bases:

y=e^(^3^t^{^9}^)e^C

The term e^C is just another constant, so with impunity, I can absorb everything into a single constant:

y=Ce^(^3^t^{^9}^)

To check the answer by differentiation, you require the chain rule. Differentiating an exponential gives back the exponential, but you must multiply by the derivative of the inside. We get:

\frac{d}{dx} (y)=\frac{d}{dx}(Ce^(^3^t^{^9}^))

\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*\frac{d}{dx}(3t^9)

\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*27t^8

Now check if the derivative equals the right side of the original differential equation:

(Ce^(^3^t^{^9}^))*27t^8=27t^8*y(t)

Ce^(^3^t^{^9}^)*27t^8=27t^8*Ce^(^3^t^{^9}^)

QED

I unfortunately do not have enough room for your second question. It is the exact same type of differential equation as the one solved above. The only difference is the fractional exponent, which would make the problem slightly more involved. If you ask your second question again on a different problem, I'd be glad to help you solve it.

7 0
2 years ago
20 EASY POINTS PLUS BRAINLIEST IF YOU ANSWER THIS QUESTION
GarryVolchara [31]

Mark me as Brainliest Please

4 0
2 years ago
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