Answer:
The mass of 2.0 mol of C02 is 44 grams
Explanation:
The weight of CO2 is 44 grams per mole (1 x 12 grams/mole for the carbon and 2 x 16 grams/mole for the oxygen atoms)
Answer:
2.00 × 10⁻³ g
Explanation:
Step 1: Write the balanced decomposition reaction
2 NaHCO₃ ⇒ Na₂CO₃ + CO₂ + H₂O
Step 2: Calculate the moles corresponding to 0.0118 g of Na₂CO₃
The molar mass of Na₂CO₃ is 105.99 g/mol.
0.0118 g × 1 mol/105.99 g = 1.11 × 10⁻⁴ mol
Step 3: Calculate the moles of H₂O produced with 1.11 × 10⁻⁴ moles of Na₂CO₃
The molar ratio of Na₂CO₃ to H₂O is 1:1. The moles of H₂O produced are 1/1 × 1.11 × 10⁻⁴ mol = 1.11 × 10⁻⁴ mol.
Step 4: Calculate the mass corresponding to 1.11 × 10⁻⁴ moles of H₂O
The molar mass of H₂O is 18.02 g/mol.
1.11 × 10⁻⁴ mol × 18.02 g/mol = 2.00 × 10⁻³ g
Answer:
Water has polar O-H bonds. The negative O atoms attract the positive H atoms in nearby molecules, leading to the unusually strong type of dipole-dipole force called a hydrogen bond. Since water has hydrogen bonds, it also has dipole-induced dipole and London dispersion forces.
Hope it helped!!
Answer: 0.8g/cm^3
Explanation:
In seeing your problem, I see an issue with your units for centimeter. The volume is in the third dimension, so we use cm^3 every single time for the volume. That way, we can arrive to the correct density (in g/cm^3)
Density = mass/volume and so
Density = 8g/10cm^3
= 0.8g/cm^3
