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aalyn [17]
3 years ago
7

Magnesium reacts with oxygen to form two compounds. Compound A contains 7.88 g of magnesium for every 15.68 g of oxygen. Compoun

d B contains 2.12 g of magnesium for every 6.91 g of oxygen. What is the mass ratio of magnesium rounded to the nearest whole number
Chemistry
1 answer:
Marina CMI [18]3 years ago
4 0

Answer:

Mass ratio of magnesium =  2 : 1

Explanation:

Let us write down the masses of element involve to form the compounds .

Compound A → 7.88 g of mg and 15.68 g of 02

Compound B → 2.12 g of mg and 6.91 g of 02

since we want to get the mass ratio of magnesium, we divide the mass of mg with the other element present (oxygen) . we want to make both compound in equal proportions.

Compound A →  7.88 / 15.68  = 0.5025510204 g of Mg /1 g of Oxygen

Compound B  →  2.12 / 6.91  = 0.30680173661  g of Mg/ 1 g of Oxygen

Mass ratio of magnesium = compound A(Mg)/compound B(Mg)

Mass ratio of magnesium = 0.5025510204/0.30680173661  

Mass ratio of magnesium = 1.63803186368 /1

Mass ratio of magnesium =  2 : 1

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68.3 grams of sodium hydroxide reacts with 78.3 grams of magnesium nitrate. ____ grams of magnesium hydroxide will form from thi
Vera_Pavlovna [14]

Answer:

30.8 grams of magnesium hydroxide will form from this reaction, and magnesium nitrate is the limiting reagent.

Explanation:

The reaction that takes place is:

  • 2NaOH + Mg(NO₃)₂ → 2NaNO₃ + Mg(OH)₂

Now we <u>convert the given masses of reactants to moles</u>, using their respective <em>molar masses</em>:

  • 68.3 g NaOH ÷ 40 g/mol = 1.71 mol NaOH
  • 78.3 g Mg(NO₃)₂ ÷ 148.3 g/mol = 0.528 mol Mg(NO₃)₂

0.528 moles of Mg(NO₃)₂ would react completely with (0.528 * 2) 1.056 moles of NaOH. There are more than enough NaOH moles, so NaOH is the reagent in excess and <em>Mg(NO₃)₂ is the limiting reagent.</em>

Now we <u>calculate how many Mg(OH)₂ are produced</u>, using the <em>moles of the limiting reagent</em>:

  • 0.528 mol Mg(NO₃)₂ * \frac{1molMg(OH)_2}{1molMg(NO_3)_2} = 0.528 mol Mg(OH)₂

Finally we convert Mg(OH)₂ moles to grams:

  • 0.528 mol Mg(OH)₂ * 58.32 g/mol = 30.8 g
7 0
2 years ago
You drop an unknown substance that weighs 8.3g into a graduated cylinder with 6ml of water. The water rises to 8ml when you drop
valkas [14]

Answer:

<h3>The answer is 4.15 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass of object = 8.3 g

volume = final volume of water - initial volume of water

volume = 8 - 6 = 2 mL

So we have

density =  \frac{8.3}{2}  \\

We have the final answer as

<h3>4.15 g/mL</h3>

Hope this helps you

7 0
3 years ago
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3 years ago
How can the knowledge of a material’s chemical makeup or use be utilized?
shutvik [7]

To identify minerals

Each material chemical makeup are a variety of chemical compounds which has each own category. They have different functional groups which helps people identify which material they look for. For instance, hydroxyl group has chemical makeup of alcohol

6 0
3 years ago
Read 2 more answers
How is impure copper refined by electrolysis
Gelneren [198K]

Answer:

By giving electricity to copper compound solution.

Explanation:

Electrolysis is one of the major way of refined copper. The copper containing solution has two electrodes.i) positive electrodes called anode. ii) negative electrodes called cathode. When electricity is pass into the copper containing solution electrolysis process is starts and impure copper is formed in anode and pure copper is formed in cathode.

So, We can get pure copper in cathode through electrolysis.

I Hope this will be helpful for you.

If this is helpful for you .Then choose this answer as brainliest answer.

6 0
3 years ago
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