What is the equilibrium expression for the reaction below?
1 answer:
Answer:
A.
Explanation:
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In this case, for us to figure out the appropriate equilibrium expression, it will be firstly necessary for us to recall the law of conservation of mass which states that the equilibrium constant of an equilibrium chemical reaction is written by dividing the products and reactants and including the stoichiometric coefficients as exponents. In such a way, for the given reaction, we will have:
As N2O is the product whereas N2 and O2 are reactants; thus, the equilibrium expression will be A.
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Answer:
-7.34 kilo Joules is the change in enthaply when 20.0 grams of nitrogen triiodide decomposes.
Explanation:
Mass of nitrogen triiodide = 20.0 g
Moles of nitrogen triiodide =
According to reaction, 2 moles of nitrogen triiodide gives 290.0 kilo Joules of heat on decomposition ,then 0.05063 moles of nitrogen triiodide will give :
-7.34 kilo Joules is the change in enthaply when 20.0 grams of nitrogen triiodide decomposes.
Answer:
The osmotic pressure of cell is KPa
Explanation:
As we know the osmotic pressure is equal to
Where
i is the Van Hoff factor
c is the concentration of solution
R is the ideal gas constant
and T is the temperature.
Substituting the given values, we get -
KPa