Answer: 0.887 g of
should be added to excess HCl(aq).
Explanation:
According to ideal gas equation:

P = pressure of gas = 805 torr = 1.06 atm (760torr=1atm)
V = Volume of gas = 235 ml = 0.235 L
n = number of moles = ?
R = gas constant =
T =temperature =



According to stoichiometry:
1 mole of chlorine is produced by = 1 mole of 
Thus 0.0102 moles of chlorine is produced by =
moles of 
Mass of
=
0.887 g of
should be added to excess HCl(aq).
Answer:
= 4.37*10^-9 M
Explanation:
We know that;
pH + pOH = 14
Therefore;
pH = 14 - pOH
Which means; pH = 14 - 5.64
= 8.36
But;
pH = -log[H3O+]
Thus;
8.36 = -log[H3O+]
[H3O+] = 10^(-8.36)
= 4.37*10^-9 M