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german
3 years ago
5

Two objects 5 kg and 7 kg are attached to the end of inextensible string which passes over frictionless pulley

Physics
1 answer:
Bumek [7]3 years ago
3 0

Answer:

ans:

tenson(T) = 20 N

acceleration (a) = 2.86 m/s

Explanation:

T + mg = Mg

T = Mg - mg

T = g( M - m )

T = 10× ( 7-5 )

T = 20 N

again;

T = 20

Ma = 20

a = 20 / 7

= 2.86 m/s

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What is the the acceleration of a proton that is 4.0 cm from the center of the bead? input positive value if the acceleration is
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Missing detail in the text:
"<span>A small glass bead has been charged to + 25 nC "

Solution
The force exerted on a charge q by an electric field E is given by
</span>F=qE
<span>Considering the charge on the bead as a single point charge, the electric field generated by it is
</span>E=k_e  \frac{Q}{r^2}
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F=qE=1.6\cdot 10^{-19}C \cdot 1.4\cdot 10^5 V/m=2.25\cdot 10^{-14} N

And finally, we can use Newton's second law to calculate the acceleration of the proton. Given the proton mass, m=1.67\cdot 10^{-27} kg, we have
F=ma
a= \frac{F}{m}= \frac{2.25\cdot 10^{-14} N}{1.67\cdot 10^{-27} kg}=1.35 \cdot 10^{13} m/s^2

The charge on the bead is positive, and the proton charge is positive as well, therefore the proton is pushed away from the bead, so:
a=-1.35 \cdot 10^{13} m/s^2
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