(a) The lunch angle is 64.8⁰
(b) The initial speed of the pass when the angle of projection is 25⁰ is 21.2 m/s
(c) The time of flight of the bullet is 1.83 s
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The given parameters include;
time of flight, T = 3.97 s
initial velocity, u = 21.5 m/s
(a) The lunch angle is calculated from the equation of motion of time of flight;
(b) the initial speed of the pass when the angle of projection is 25⁰ and range of 35 m, is calculated as follows;
(c) The time of flight of the bullet is calculated as;
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Answer:
speed cannot be used to calculate the temperature
What’s the question? I’d isn’t understand explain
You multiply the length of time by the speed, to get 100m/s