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2 years ago

10

Gravitational force between two objects depends on

2 answers:

Andrew [12]2 years ago

7 0

Answer:

SIZE AND DISTANCE BETWEEN THEM

Jobisdone [24]2 years ago

6 0

Their masses and the distance between them

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if the vapor's volume were to be incorrectly recorded as 125ml, how will this error affect the calculated molar mass of the unkn

diamong [38]

So base on your question that as if the vapors volume were to incorrectly recorded as 125ml, the effect of the error to calculate the molar mass is the same as the error in measuring the volume of the vapor. I hope you are satisfied with my answer and feel free to ask for more

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3 years ago

The physical structure of the earth’s rock is changed by _____.

PSYCHO15rus [73]

It could be stress or strain

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3 years ago

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The wavelength of visible light is about 5500 times longer than the wavelength of x-rays. If you represent the wavelenth of an x

Pie

Answer:

458.33 ft

Explanation:

We are given that

Wavelength of of an x- ray photon=1 in

Wavelength of of an x- ray photon== $\frac{1}{12}$ ft

1 in= $\frac{1}{12}$ feet

We have to find the length of line (in feet) drawn by you to represent the wavelength of visible light.

According to question

Wavelength of visible light= $5500\times \frac{1}{12}$ ft

Wavelength of visible light $=\frac{5500}{12}$ ft

Wavelength of visible light=458.33 ft

Hence, the 458.33 ft line must drawn by you to represent the wavelength of visible light.

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3 years ago

In which layer of the sun is energy transfferred between atoms?

sasho [114]

Answer:

Core is the layer of the sun is energy transferred between atoms.

Explanation:

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2 years ago

It requires 49 J of work to stretch an ideal very light spring from a length of 1.4 m to a length of 2.9 m. What is the value of

nadya68 [22]

Answer:

44 N/m

Explanation:

The extension, e, of the spring = 2.9 m - 1.4 m = 1.5 m

The work needed to stretch a spring by <em>e</em> is given by

$W = \frac{1}{2} ke^2$

where <em>k</em> is spring constant.

$k = \dfrac{2W}{e^2}$

Using the appropriate values,

$k = \dfrac{2\times 49\text{ J}}{1.5^2\text{ m}^2} = 43.55\ldots\text{ N/m} \approx 44\text{ N/m}$

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2 years ago

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