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Rutherford overturned Thomson's model in 1911 with his well-known gold foil experiment in which he demonstrated that the atom has a tiny and heavy nucleus. Rutherford designed an experiment to use the alpha particles emitted by a radioactive element as probes to the unseen world of atomic structure.
Answer:
The direction of the car’s change in linear momentum is 149.04° West of North
Explanation:
Momentum is defined as the product of mass of a body and its velocity
Momentum = mass × velocity
Change in Momentum = mass × change in velocity
∆P = m∆v
∆P = m(v-u)
Given m = 1500kg
v = 25m/s
u = 15m/s
∆P = 1500(25-15)
∆P = 1500×10
∆P = 15,000kgm/s
Since the car first travels due East i.e +x direction
x = 25m/s
Travelling due south is negative y direction
y = -15m/s
Direction of the car change
θ = tan^-1(y/x)
θ = tan^-1(-15/25)
θ = tan^-1(-0.6)
θ = -30.96°
Since tan is negative in the second quadrant
θ = 180-30.96
θ = 149.04°
The direction of the car’s change in linear momentum is 149.04° West of North
Answer:
find acceleration first
a = vf - vi / t
a = 0 - 1.5 / 0.5s (vf is zero)
a = -3 (negative sign indicates that acceleration is decreasing)
so F=ma
F = 35 x -3
F = -105 N (here negative sign indicates that u have to apply a force opposite to the boy's direction i.e from the left or towards the right)
Explanation:
