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irakobra [83]
2 years ago
11

In a PE class, the teacher requires his students to monitor periodically their progress towards the fitness goals. Which of thes

e should be done by the students before and after an activity? *
a. weight monitoring
b. monitor pulse rate
c. warm up and cool down activities
d. physical check-up
Physics
1 answer:
pav-90 [236]2 years ago
8 0
The answer would be c warm up and cool down because before you do an activity stretching is very important
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A length of copper wire carries a current of 14 A, uniformly distributed through its cross section. The wire diameter is 2.5 mm,
gavmur [86]

Answer:

a. ρ_\beta=1.996J/m^3

b. U_E=9.445x10^{-15} J/m^3

Explanation:

a. To find the density of magnetic field given use the gauss law and the equation:

i=14A, d=2.5mm, R=3.3Ω, l=1 km, E_o=8.85x10^{-12}F/m, u_o=4*x10^{-7}H/m

ρ_\beta=\frac{\beta^2}{2*u_o}

ρ_\beta=\frac{1}{2*u_o}*(\frac{u_o*i^2}{2\pi *r})^2

ρ_\beta=\frac{u_o*i^2}{8\pi*r}=\frac{4\pi *10^{-7}H/m*(14A)^2}{8\pi*(1.25x10^{-3}m)^2}

ρ_\beta=1.996J/m^3

b. The electric field can be find using the equation:

U_E=\frac{1}{2}*E_o*E^2

E=(\frac{i*R}{l})^2

U_E=\frac{1}{2}*8.85x10^{-12}*(\frac{14A*3.3}{1000m})^2

U_E=9.445x10^{-15} J/m^3

4 0
3 years ago
At the local hockey rink, a puck with a mass of 0.12kg is given an initial speed of 5.3m/s. If the coefficient of friction betwe
Salsk061 [2.6K]
Here’s my work to your question. I used Newton’s Second Law and a kinematics equation to arrive at the answer.

5 0
2 years ago
PLEASE HELP ME , it’s my exam
tatyana61 [14]

Answer:

I only know how to answer 22

which is 250 J

Explanation:

KE: 1/2 mv^2

m- 5kg

v- 10 m/s

KE: 1/2 × 5 × 10^2

= 250 J

5 0
3 years ago
What is the amount of time for one cycle to to occur
stich3 [128]
<h2 /><h2>\\</h2><h2><u>3</u><u>6</u><u>5</u><u> </u><u>DAYS</u></h2>

Period, being a time, is measured in units of time such as seconds, hours, days or years. The period of orbit for the Earth around the Sun is approximately 365 days; it takes 365 days for the Earth to complete a cycle

\\

Hope It Helps!

3 0
2 years ago
A negative charged particle of known magnitude qis placed in a uniform electric field of known strength E. What additional infor
zalisa [80]

Answer:

Explanation:

Force on a charged particle placed in an Electric field is given by the product of the magnitude of Electric Field and charge on the particle.

The direction of the force will be given by the nature of a charge on the particle. If the charge is positively charged then the force acting will be in the direction of the Electric field.  

If the charge is negatively charged then force acting will be opposite to the direction of the electric field.

Thus no extra information is needed to determine the direction of force.

6 0
3 years ago
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