Answer:
99% Confidence interval is given as;
Lower Limit = 0.062
Upper Limit = 0.130
Step-by-step explanation:
Given the data in the question;
x = 48
n = 500
sample proportion p = x/n = 48/500 = 0.096
with 99% confidence
significance level ∝ = 1 - 99% = 1 - 0.99 = 0.01
∝/2 = 0.01 / 2 = 0.005
Critical Z-value = = = 2.576
Now,
Standard error of p : SE = √[ (p × ( 1 - p) / n ) ]
we substitute
SE = √[ (0.096 × ( 1 - 0.096) / 500 ) ]
SE = √[ (0.096 × 0.904) / 500 ]
SE = √[ 0.086784 / 500 ) ]
SE = 0.0131745
so
Margin of Error E = × SE
E = 2.576 × 0.0131745
E = 0.0339
Now 99% confidence interval will be
⇒ 0.096 ± 0.0339
⇒ (0.096 - 0.0339, 0.096 + 0.0339 )
⇒ ( 0.062, 0.130 )
Lower Limit = 0.062
Upper Limit = 0.130
Step-by-step explanation:
v=l×b×h
300cm²=4×3x×x
300÷12=x²
x=5
3x=3×5=15
a=15×5
2. 012
The decimal places count left to right in powers of 1/10, similar to how the whole number places count right to left in powers of 10.
0.1 is one tenth.
0.01 is one hundredth.
0.001 is one thousandth.
0.0001 is one ten thousandth.
Answer:B
Step-by-step explanation:because im smart