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icang [17]
3 years ago
15

In which number does one digit 6 have a value of 1 /100 of the other 6?

Mathematics
1 answer:
maw [93]3 years ago
8 0

Answer:

The answer is C.

Step-by-step explanation:

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PLEASE HELP!! brainliest if correct!!
Sonja [21]
Graph #1: No
Graph #2: Yes
Graph #3: No
Graph #4: No
Graph #5: No
Graph #6: Yes

Reasoning:

The vertical line test is a test that determines wether a graph is a function or a relation. The vertical line test shows that if you construct a vertical line through any point on the graph, then the vertical line should only intercept the graph once for it to be a function.
6 0
2 years ago
Help ME fast and pls
iogann1982 [59]

Answer:

the first one is 8 and 9

the second one is 13 and 14

Step-by-step explanation:

8^2 is equal to the square root of 64 and 9^2 is equal to the square root of 81.

13^2 is equal to the square root of 169 and 14^2 is equal to the square root of 196.

hope this helps and is correct.

5 0
3 years ago
Please help me for the love of God if i fail I have to repeat the class
Elena-2011 [213]

\theta is in quadrant I, so \cos\theta>0.

x is in quadrant II, so \sin x>0.

Recall that for any angle \alpha,

\sin^2\alpha+\cos^2\alpha=1

Then with the conditions determined above, we get

\cos\theta=\sqrt{1-\left(\dfrac45\right)^2}=\dfrac35

and

\sin x=\sqrt{1-\left(-\dfrac5{13}\right)^2}=\dfrac{12}{13}

Now recall the compound angle formulas:

\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta

\cos(\alpha\pm\beta)=\cos\alpha\cos\beta\mp\sin\alpha\sin\beta

\sin2\alpha=2\sin\alpha\cos\alpha

\cos2\alpha=\cos^2\alpha-\sin^2\alpha

as well as the definition of tangent:

\tan\alpha=\dfrac{\sin\alpha}{\cos\alpha}

Then

1. \sin(\theta+x)=\sin\theta\cos x+\cos\theta\sin x=\dfrac{16}{65}

2. \cos(\theta-x)=\cos\theta\cos x+\sin\theta\sin x=\dfrac{33}{65}

3. \tan(\theta+x)=\dfrac{\sin(\theta+x)}{\cos(\theta+x)}=-\dfrac{16}{63}

4. \sin2\theta=2\sin\theta\cos\theta=\dfrac{24}{25}

5. \cos2x=\cos^2x-\sin^2x=-\dfrac{119}{169}

6. \tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}=-\dfrac{24}7

7. A bit more work required here. Recall the half-angle identities:

\cos^2\dfrac\alpha2=\dfrac{1+\cos\alpha}2

\sin^2\dfrac\alpha2=\dfrac{1-\cos\alpha}2

\implies\tan^2\dfrac\alpha2=\dfrac{1-\cos\alpha}{1+\cos\alpha}

Because x is in quadrant II, we know that \dfrac x2 is in quadrant I. Specifically, we know \dfrac\pi2, so \dfrac\pi4. In this quadrant, we have \tan\dfrac x2>0, so

\tan\dfrac x2=\sqrt{\dfrac{1-\cos x}{1+\cos x}}=\dfrac32

8. \sin3\theta=\sin(\theta+2\theta)=\dfrac{44}{125}

6 0
3 years ago
If ab= 7x-6 and bc= 12-2x. Then what does ac equal?
ra1l [238]
Ab = (7x-6) →   b = (7x-6)/a   (1)

bc = (12-2x) → b = (12-2x)/c   (2)

Since (1) = (2) → (7x-6)/a = (12-2x)/c OR  a/c = (7x-6)/(12-2x)  (3)

Multiply  both numerators of (3) by the SQUARE of their  respective denominators;

(a*c²)/c = (7x-6)(12-2x)²/(12-2x)
Now simplify:

ac = (7x-6)(12x-2x)  or ac = -14x² + 96x - 72


4 0
3 years ago
Can I conclude ? (Please don’t be wrong I’ll give brainlist)
Crazy boy [7]
Yes, by SAS theorem.
4 0
3 years ago
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