Answer: The number is 15.
Step-by-step explanation: We are given a certain number we don't know about. Since it's value is unknown it is a variable. We'll call this variable "x". That number, x, is divided by <em>3</em>, and then <em>3 </em>was added to x to make <em>8</em>. So then if x = <em>15</em>, then dividing it by <em>3 </em>would make <em>5</em>, and adding <em>3 </em>to that would make <em>8</em>.
Another way to solve this, or check your work, is to work the problem out in reverse. Starting with the number <em>8</em>, subtract <em>3 </em>and then multiply that number by <em>3</em>. This will give you the number 15. Which shows that the answer is correct.
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Thus the number is 15. Hope this helps, and have a great day!
Answer:
That would be;
+52-20
Step-by-step explanation:
From the first part, he gained/earned 52 points
This is a positive so we have + 52
In the second round , he lost 20
This is a negative so we have - 20
Writing this as an addition problem, it will be;
+52-20
Answer:
- left: a, 0.4A; b, 0.4A; c, 0.4A; d, 0.4A; e, 0.8A
- right: a, 0.4A; b, 0.2A; c, 0.4A, d, 0.2A; e, 0.6A
Step-by-step explanation:
The currents into and out of a single device are the same. The sum of currents into and out of a junction are the same.
<u>Left Circuit</u>
The two branches at the bottom of the circuit are identical, so will have the same current. The current in each branch will be half the current shown coming from the battery:
a = b = c = d = (0.8 A)/2 = 0.4 A
The current at e into the battery will be the same as the current shown coming out of the battery:
e = 0.8 A
__
<u>Right Circuit</u>
0.6 A is the sum of the currents into the two branches. The current in the bottom branch is shown as 0.2 A, so the current in the top branch must be 0.4 A. That way, the currents total 0.6 A.
As before, the current throughout any given branch is the same, so ...
a = c = 0.4 A
b = d = 0.2 A
e = 0.6 A
Answer:
A) y^3+27
Step-by-step explanation:
There are two ways of solving this problem:
1. Recognizing this as the factored form of the sum of perfect cubes
2. Distribute and add the like terms.
1. In order to distribute we must multiply y by y^2-3y+9, and then 3 by y^2-3y+9:
After we add the positive and negative 3y^2 and 9y, they will cancel out and be gone entirely:
2. You know how you can factor the difference of perfect squares?
As an example:
Well, not many people know this but you can actually factor both the sum and difference of perfect cubes:
Because we have these identities, we can easily establish here that we have the sum of perfect cubes, and that (y+3)(y^2-3y+9)= y^3+3^3 = y^3+27
X = -4. Hope this helps ;)
