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DiKsa [7]
3 years ago
11

36

Chemistry
2 answers:
Alex_Xolod [135]3 years ago
7 0

Answer: kr

Explanation:

LiRa [457]3 years ago
4 0
Omg that is that ( but I do not know this
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Is the erbium transparent, translucent or opaque?
nexus9112 [7]

Objects that allow all of the light to pass through them is said to be transparent. One can clearly see through the transparent objects.  Objects that allow only some light to pass through them is said to be translucent. One can partially see through the translucent objects whereas  objects that do not allow any light to pass through them is said to be opaque. One cannot see through the opaque objects at all.

Erbium is a chemical element with atomic symbol, Er which belongs to the period 6 with atomic number 68. It is a lanthanide, which is silvery-white solid metal in nature. The metals are opaque to visible lights.

Hence, erbium is opaque.

7 0
3 years ago
25.0 grams of Iron (III) oxide reacts with 30.0 grams of Silver sulfate in a double replacement reaction. Find the
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Answer:

iron

Explanation:

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3 0
3 years ago
A sample of ethane (C2H6)was combusted completely and the water that formed has a mass of 1.61 grams.How much ethane, in grams,
ruslelena [56]

Answer:

0.89 g of ethane

Explanation:

The balanced reaction equation is

C2H6(g) + 7/2 O2(g) -----------> 2CO2(g) + 3H2O(g)

From this balanced reaction

30g of ethane yields 54g of water

Therefore mass of ethane necessary to obtain 1.61g of water we have:

30 × 1.61/54 = 0.89 g of ethane

5 0
4 years ago
Cities are measurably hotter than the surrounding suburbs
abruzzese [7]
 cities have factories , more people and no water around .
5 0
3 years ago
Read 2 more answers
How many liters of 4.0 NaOH solution will react with 1.8 mol H2SO4
wlad13 [49]

Answer:

0.9 liters of 4.0 M NaOH solution will react with 1.8 moles of sulfuric acid.

Explanation:

2NaOH(aq)+H_2SO_4(aq)\rightarrow Na_2SO_4(aq)+2H_2O(l)

According to reaction, 1 mole of sulfuric acid reacts with 2 moles of sodium hydroxide.

Then 1.8 moles of sulfuric acid will react with:

\frac{2}{1}\times 1.8 mol=3.6 mol moles of NaOH.

Molarity of NaOH = 4.0 M

Moles of NaOH= n = 3.6 mol

Volume of NaOH = V

M=\frac{n}{V(L)}

V=\frac{n}{M}=\frac{3.6 mol}{4.0 M}=0.9 L

0.9 liters of 4.0 M NaOH solution will react with 1.8 moles of sulfuric acid.

8 0
3 years ago
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