Answer:
D. two real solutions
Step-by-step explanation:
p²+5 = 6p
p² - 6p +5 =0
D = b² - 4ac = (-6)² - 4*(1)*5 = 36 - 20 = 16
D > 0, so this equation has 2 real solutions
Answer:
Probability that a randomly selected woman's gestation period will be between 261 and 279 days is 0.68.
Step-by-step explanation:
We are given that the average human gestation period is 270 days with a standard deviation of 9 days. The period is normally distributed.
Firstly, Let X = women's gestation period
The z score probability distribution for is given by;
Z =
~ N(0,1)
where,
= average gestation period = 270 days
= standard deviation = 9 days
Probability that a randomly selected woman's gestation period will be between 261 and 279 days is given by = P(261 < X < 279) = P(X < 279) - P(X
261)
P(X < 279) = P(
<
) = P(Z < 1) = 0.84134
P(X
261) = P(
) = P(Z
-1) = 1 - P(Z < 1)
= 1 - 0.84134 = 0.15866
<em>Therefore, P(261 < X < 279) = 0.84134 - 0.15866 = 0.68</em>
Hence, probability that a randomly selected woman's gestation period will be between 261 and 279 days is 0.68.
Answer:
-3-5i
Step-by-step explanation:
Answer:
(-12, -12)
Step-by-step explanation:
Since the scale factor is 3, you would multiply the x-coordinate and y-coordinate by it.
-4×3=-12
Hope this helps!!