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Vedmedyk [2.9K]
3 years ago
14

How many moles of iron (Fe) will be produced from 6.20 moles of carbon monoxide (CO) reacting with excess iron (III) oxide (Fe2O

3)?​
If you can, please show the work because I really don't understand and ya girl is struggling. thank you guysss <33
Chemistry
1 answer:
bonufazy [111]3 years ago
8 0

Answer:

4.13 moles of Fe

Explanation:

Step 1: Write the balanced equation

3 CO + Fe₂O₃ ⇒ 2 Fe + 3 CO₂

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of CO to Fe is 3:2.

Step 3: Calculate the moles of Fe formed from 6.20 moles of CO

We will use the previously established molar ratio.

6.20 mol CO × 2 mol Fe/3 mol CO = 4.13 mol Fe

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anyanavicka [17]

Balanced chemical equation is  -  3Fe2+ + NO3- + 4H+ → 3Fe3+ + NO + 2H2O

Fe2+ + NO3- + H+ → Fe3+ + NO3- + NO + H2O

Fe+22+ + N+5O-23- + H+1+ → Fe+33+ + N+5O-23- + N+2O-2 + H+12O

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A balanced chemical equation specifies the quantities of reactants and products required to meet the Law of Conservation of Mass. This signifies that there is the same number of each sort of atom on the left side of the equation as there are on the right side. The rule of a balanced chemical equation is used to determine if two weights put on opposing sides of the fulcrum will balance each other.

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3 0
2 years ago
Based on the properties in Table 1, which example describes the best use of nitinol in a manufactured product?
nekit [7.7K]

Answer: D- making flexible eyeglass frames

Explanation: my powerful mind

3 0
3 years ago
Cómo se clasifican los tipos de nutrientes​
Semenov [28]

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6 0
3 years ago
1. Magnesium chloride solution reacts with silver nitrate solution to form magnesium nitrate
Whitepunk [10]

a. 1,4332 g

b. 7.54~g

<h3>Further explanation</h3>

Given

Reaction

MgCl2 (s) + 2 AgNO3 (aq) → Mg(NO3)2 (aq) + 2 AgCl (s)

20 cm of 2.5 mol/dm^3 of MgCl2

20 cm of 2.5 g/dm^3 of MgCl2

Required

the mass of silver chloride - AgCl

Solution

a. mol MgCl2 :

\tt 20~cm^3=20\times 10^{-3}~dm^3\\\\mol=M\times V\\\\mol=2.5~mol/dm^3\times 20\times 10^{-3}DM^3=0.05

From equation, mol AgCl = 2 x mol MgCl2=2 x 0.05=0.1

mass AgCl(MW=143,32 g/mol)= 0.1 x 143,32=1,4332 g

b. mol MgCl2 (MW=95.211 /mol):

\tt mol=M\times V\\\\mol=\dfrac{2.5~g/dm^3}{95,211 g/mol}=0.0263~mol/dm^3

From equation, mol AgCl = 2 x mol MgCl2=2 x 0.0263=0.0526

mass AgCl(MW=143,32 g/mol)= 0.0526 x 143,32=7.54~g

6 0
3 years ago
The quantity, q grams, of the radioactive isotope strontium-90 present in a sample decreases by half over a period of about t =
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Notice q=3/2, is half of the original q = 3(<span>1/2</span>)<span>t/28.8
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8 0
3 years ago
Read 2 more answers
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