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3 years ago

Which of the following objects is NOT accelerating?

Physics

1 answer:

MatroZZZ [7]3 years ago

4 0

Answer:

A Bicycle

Explanation:

A Space shuttle accelerating because the Earth pulls on it through the gravitational force.

A Truck is accelerating because acceleration is necessary for an object to change direction.

A car is accelerating because it is speeding up unexpectedly?????

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How can you write a sentence using gland and hormone in the same sentence?

zmey [24]

Did you know that hormones are produced and they are released by glands?

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3 years ago

A falling stone is at a certain instant 90 feet above the ground. two seconds later it is only 10 feet above the ground. if it w

choli [55]

The equation relevant to this is:

S(t) = So + Vot - At²/2

Therefore we can create two equations:
S(t) = 90 = So - 4t - 16.1t² --> eqtn 1
S(t+2) = 10 = So - 4(t+2) - 16.1(t+2)² --> eqtn 2

Expanding eqtn 2:
10 = So - 4t - 8 - 16.1(t² + 4t + 4)
10 = So - 4t - 8 - 16.1t² - 64.4t - 64.4
10 + 8 + 64.4 = So - 68.4t - 16.1t²
82.4 = So - 68.4t - 16.1t² --> eqtn 3

Subtracting eqtn 1 by eqtn 3:

90 = So - 4t - 16.1t²

82.4 = So - 68.4t - 16.1t²

=> 7.6 = 64.4t

t = 0.118 s

Therefore calculating for initial height So:

82.4 = So - 68.4(0.118) - 16.1(0.118)²

So = 90.7 ft

7 0

3 years ago

A glider of mass 5.0 kg hits the end of a horizontal rail and bounces off with the same speed, in the opposite direction. The co

NeTakaya

To solve the exercise it is necessary to apply the concepts given in Newton's second law and the equations of motion description.

Let's start by defining acceleration based on speed and time, that is

$a = \frac{v}{t}$

On the other hand according to Newton's second law we have to

F=ma

where

m= Mass

a = Acceleration

Replacing the value of acceleration in this equation we have

$F=m(\frac{v}{t})$

Substituting with our values we have

$100N=(5Kg)\frac{v}{0.2}$

Re-arrange to find v

$v=\frac{100*0.2}{5}$

$v = 2m/s$

Therefore the speed of the glider is 2m/s

5 0

3 years ago

Car and a train move together along straight, parallel paths with the same constant cruising speed v0. At t=0 the car driver not

musickatia [10]

Answer:

Part A: $t = v_0/a_0$

Part B: $t = v_0/a_0$

Part C: $v_0^2/a_0$

Explanation:

Part A:

We will use the following kinematics equation:

$v = v_0 + at\\0 = v_0 - a_0t\\t = \frac{v_0}{a_0}$

Part B:

We will use the same kinematics equation:

$v = v_0 + at\\v_0 = 0 + a_0t\\t = \frac{v_0}{a_0}$

Part C:

The total time takes is 2t.

So the train moves a distance of

$x = v_0(2t) = 2v_0(\frac{v_0}{a_0}) = \frac{2v_0^2}{a_0}$

And the car moves a distance in Part A and in Part B:

$d_A = v_0t + \frac{1}{2}at^2 = v_0(\frac{v_0}{a_0}) - \frac{1}{2}a_0(\frac{v_0^2}{a_0^2}) = \frac{v_0^2}{a_0} - \frac{v_0^2}{2a_0} = \frac{v_0^2}{2a_0}\\d_B = v_0t + \frac{1}{2}at^2 = 0 + \frac{1}{2}a_0(\frac{v_0^2}{a_0^2}) = \frac{v_0^2}{2a_0}$

So the total distance that the car traveled is $d = \frac{v_0^2}{a_0}$

The difference between the train and the car is

$x - d = \frac{2v_0^2}{a_0} - \frac{v_0^2}{a_0} = \frac{v_0^2}{a_0}$

8 0

3 years ago

I need help on this which is correct? plz help me its timed.

mario62 [17]

Answer:

Watershed should be your answer!

3 0

3 years ago