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Pavlova-9 [17]
3 years ago
5

Light from a red laser pointer has a speed of 3.0×10^8 m/s and has a wavelength of 6.5×10^−7 m . What is the frequency of this l

ight?
A.
2.0×10^2 m^2/s
B.
4.6×10^14 1/s
C.
4.6 s
D.
2.2×10^−15 s
Physics
2 answers:
Art [367]3 years ago
8 0

Answer:

B.

4.6×10^14 1/s

Explanation:

v = f × lambda

Where,

v is the velocity

f is the frequency

Lambda is the wavelength

3.0 × 10⁸ = f × 6.5 × 10^-7

f = (3 × 10⁸) ÷ (6.5 × 10^-7)

f = (3/6.5) × 10^(8 - -7)

f = 0.4615384615 × 10¹⁵

f = 4.615384615 × 10¹⁴

Vaselesa [24]3 years ago
6 0

Answer:

the answer is b

Explanation:

because you multiply speed times wavelength

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A 645 g block is released from rest at height h0 above a vertical spring with spring constant k = 530 N/m and negligible mass. T
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d)0.24m

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W= \frac{1}{2}kx² = \frac{1}{2}(530)(0.149)² =  5.88 J

b)  Workdone by the spring = - Workdone by the block = -5.88J

c) Taking x = 0 at the contact point we have U top = U bottom

So, mgh_o = \frac{1}{2}kx² - mgx

And, h_o= ( \frac{1}{2}kx² - mgx )/(mg) = [\frac{1}{2} (530)(0.149^2)-(0.645)(9.8)(0.149)]/(0.645x9.8)    

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h_o = 3 x 0.78 = 2.34m

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\frac{1}{2}(530)x²  - [(0.645)(9.8)x] - [(0.645)(9.8)(2.34) = 0

265x² - 6.321x - 14.8 = 0  

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