Given :
A rope 6m long is fixed at one end, the other end is attached to a light string so that it is free to move.
The speed of waves on the rope is 18 m/s.
To Find :
The frequency of the second harmonic.
Solution :
We know, for second harmonic wave :
Wavelength = Length of rope

Now, we know frequency is given by :

Therefore, the frequency of the second harmonic is 3 s⁻¹.
Answer:
How will the electrostatic force be changed if the distance between two electric charges is tripled?
B) 3 times the original force
Answer:
The direction of angular velocity and angular momentum are perpendicular to the plane of rotation. Using the right hand rule, the direction of both angular velocity and angular momentum is defined as the direction in which the thumb of your right hand points when you curl your fingers in the direction of rotation.
Explanation:
Answer:
The final velocity of 18 kg ball is
= 42.09 
Explanation:
Mass of first ball
= 18 kg
Mass of second ball
= 47 kg
Initial velocity of 18 kg ball
= 76 
Initial velocity of 47 kg ball = 0
Final velocity of 18 kg ball
= ??
Final velocity of 18 kg ball is given by the formula
= 
Put all the values in above formula we get
= 2 × 18 × 
= 42.09 
Thus, the final velocity of 18 kg ball is
= 42.09 