73 cm, the perimeter is all side totals, to to find each side length you just have to divide by 4 since all the sides of a square are the same
5³ is 5x5x5 so that is 125
Answer:
D
Step-by-step explanation:
IF you count the dots for each graph, you would see that the minimum for B is Higher than group A's maximum, Therefore, the numbers do not overlap. This means that at a simple glance you can see which company does better.
Answer:
$110 and $30
Step-by-step explanation:
To solve this, we need to know the total share which is,

Then, you need to know the fraction of the share over the total, such that



So if to find how much that'll be of the $180 for the largest and smallest share,
Largest:

Smallest:

Answer:

Step-by-step explanation:
GIVEN: A bag contain
red marbles,
green marbles and
blue marble. A marble is chosen at random from the bag and not replaced, then a second marble is chose.
TO FIND: What is the probability both marbles are green.
SOLUTION:
Total marbles in bag 
total number of green marbles 
Probability that first marble will be green 

Probability that second marble will be green 

As both events are disjoint
probability both marbles are green 

Hence the probability both marbles are green is 