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Sidana [21]
3 years ago
14

what ere the different types of petrol used in petrol pumps?what is the composition of each and what type of vehicle is each sui

table for?is there a difference in the price?
Chemistry
1 answer:
Artist 52 [7]3 years ago
6 0
Petrol is primarily characterised by its octane number which defines its ability to burn efficiently and produce more energy per unit. A low octane petrol particle blast inside the engine instead of burning from spark this is called knocking as it produces knocking sound in the engine, to counter this an anti-knocking agent is added to petrol. Earlier Lead was used as an anti-knocking agent but it is highly toxic ,also the researchers who experimented lead with petrol died unnatural death. In later stages when effects of lead toxicity started showing up lead was replaced by benzene compounds as anti-knocking agents this is know as Unleaded petrol. Benzene is carcinogenic and started showing its ill effects after few years especially in densely populated cities. Govts have reduced the concentration of benzene in petrol thereafter and emphasised on implementation of Euro iv standards.
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Find the mass of one atom of uranium-235. Recall that the mass in atomic mass units is equal to the mass in grams of one mole of
stiv31 [10]

Answer:

3.90*10^{-25}kg/atom

Explanation:

The molar mass of uranium-235 is 235 g/mol. So one mole of uranium-235 has a mass of 235 g. Put differently 6.022×10^23 atoms of uranium-235 have a mass of 235 g. Knowing that, how can we use that to find the mass of one atom?

mass of one atom = \frac{235 g}{1mol} *\frac{1 mol}{6.022*10^{23}atoms } *\frac{1kg}{1000g}= 3.90*10^{-25}kg/atom

7 0
3 years ago
Why do the planets keep orbiting the sun
dsp73
There's no reason, it's just because the sun has a gravitational pull
3 0
3 years ago
________ properties depend on the amount of material present.
Kamila [148]

Answer: Extensive!

Explanation:

6 0
3 years ago
Given a sample of poly[ethylene-stat-(vinyl acetate)] A.Calculate the mean repeat unit molar mass for a sample of poly[ethylene-
AlladinOne [14]

Answer:

a) The mean repeat unit molar mass for PEVA is 30.72 g/mol

b) degree of polymerization of the copolymer is 1300

Explanation:

Given that;

the wt% of copolymer consist of 12.9 wt% of vinyl acetate and 87.1 wt% Ethylene.

Basis: 100 g of PEVA consist of 12.9 of vinyl acetate and 87.1g of Ethylene.

now we calculate the mole fraction of vinyl acetate Ethylene in the copolymer;

the molecular weights of vinyl acetate and ethylene are 86.09 g/mol and 28.05 g/mol respectively

so

moles of vinyl acetate = wt. of vinyl acetate / molecular weights of vinyl acetate

moles of vinyl acetate = 12.9 g / 86.09 g/mol

moles of vinyl acetate = 0.1498 mol

moles of Ethylene = wt. of Ethylene / molecular weights of Ethylene

moles of Ethylene = 87.1 g / 28.05  d/mol

moles of Ethylene  = 3.1052 mol

Total moles = 0.1498 mol + 3.1052 mol = 3.255 mol

Next we calculate the mole percent;

mole percent of vinyl acetate X_{V} = moles of vinyl acetate / total  moles

X_{V} = (0.1498 mol / 3.255 mol) × 100

X_{V}  = 4.6%

mole percent of Ethylene X_{E} = moles of Ethylene / total  moles

X_{E}  = (3.1052 mol / 3.255 mol) × 100

X_{E}  = 95.397% ≈ 95.4%

we know that, mean repeat unit molar mass for a sample = ∑X_{i}M_{i}

where X_{i} is the fraction ratio and M_{i} is the molecular  weight

so or the PEVA

mean repeat unit molar mass M = ( X_{V}M_{V}) + ( X_{E}M_{E})

so we substitute

M = ( 4.6% × 86.09) + ( 95.4% × 28.05 )

M = 3.96014 + 26.7597

M = 30.72 g/mol

Therefore, The mean repeat unit molar mass for PEVA is 30.72 g/mol

b)

Degree of polymerization

DP_{n} = \frac{M_{n} }{M}

where M_{n} is the number average molecular weight ( 39,870 g/mol )

so we substitute

DP_{n} = 39,870 g/mol / 30.72 g/mol

DP_{n}  = 1297.85 ≈ 1300   { 3 significance figure }

Therefore, degree of polymerization of the copolymer is 1300

5 0
2 years ago
At STP (101.3 kPa, 0 °C), what volume would 2.00 moles of oxygen gas occupy? The gas constant is 8.31
lakkis [162]

Answer:

44.8 L

Explanation:

Ideal Gas Equation -

i.e.,

PV = nRT

where,

P = pressure

V = volume

n = moles

R = universal gas constant

T = temperature

Using the information given in the question, Volume of the gas can be calculated -

P = 101.3 kPa

V = ?

n = 2.00 moles

R = 8.31

T = 0 degree C = 273.15 K

Using the above data, and putting the data in the respective formula -

PV = nRT

101.3 kPa * V = 2.00 moles * 8.31 * 273.15 K

V = 44.8 L

Hence, the volume of the given gas = 44.8 L

4 0
3 years ago
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