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2 years ago

a force 4000 n accelerates a car of mass 800 kg from rest to 20 ms how far does the car travel while the force is acting?

Physics

1 answer:

Neko [114]2 years ago

4 0

Answer:

d = 40 m

Explanation:

Given that,

Force, F = 4000 N

Mass of a car, m = 800 kg

Initial velocity, u = 0 (at rest)

Final velocity, v = 20 m/s

We need to find the distance traveled. Force acting on a car is given by :

F = ma

Where

a is the acceleration of the car.

$a=\dfrac{F}{m}\\\\a=\dfrac{4000}{800}\\\\a=5\ m/s^2$

Let it has traveled d distance. Using third equation of motion.

$v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{(20)^2-(0)^2}{2\times 5}\\\\d=40\ m$

So, the required distance is equal to 40 m.

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negative acceleration- deceleration

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3 years ago

[25 points] Imagine two billiard balls on a pool table. Ball A has a mass of 7 kilograms and ball B has a mass of 2 kilograms. T

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6 meters is left because you subtract 12 meters from 6

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3 years ago

A container with volume 1.64 L is initially evacuated. Then it is filled with 0.226 g of N2N

vaieri [72.5K]

Answer:

0.015 atm

Explanation:

The pressure of the gas can be calculated using Ideal Gas Law:

$p = \frac{nRT}{V}$

<u>Where:</u>

n: is the number of moles of the gas

R: is the gas constant = 0.082 L*atm/(K*mol)

V: is the volume of the container = 1.64 L

T: is the temperature

We need to find the number of moles and the temperature. The number of moles is:

$n = \frac{m}{M}$

<u>Where:</u>

M: is the molar mass of the N₂ = 14.007 g/mol*2 = 28.014 g/mol

m: is the mass of the gas = 0.226 g

$n = \frac{0.226 g}{28.014 g/mol} = 8.07 \cdot 10^{-3} moles$

Now, the temperature can be found using the following equation:

$v_{rms} = \sqrt{\frac{3RT}{M}}$

<u>Where:</u>

R: is the gas constant = 0.082 L*atm/K*mol = 8.314 J/K*mol

$v_{rms}$ : is the root-mean-square speed of the gas = 182 m/s

By solving the above equation for T, we have:

$T = \frac{v_{rms}^{2}*M}{3R} = \frac{(182 m/s)^{2}*28.014 \cdot 10^{-3} Kg/mol}{3*8.314 J K^{-1}mol^{-1}} = 37.20 K$

Finally, we can find the pressure of the gas:

$p = \frac{nRT}{V} = \frac{8.07 \cdot 10^{-3} mol*0.082 L*atm* K^{-1}*mol^{-1}*37.20 K}{1.64 L} = 0.015 atm$

Therefore, the pressure of the gas is 0.015 atm.

I hope it helps you!

8 0

3 years ago

A ball starts from rest and accelerates at a constant rate of 1.0m/s to a final velocity of

den301095 [7]

Answer:

Time taken to reach final velocity = 5.5 second

Explanation:

Given:

Initial velocity (Starting from rest)(u) = 0 m/s

Acceleration of ball (a) = 1 m/s²

Final velocity (v) = 5.5 m/s

Find:

Time taken to reach final velocity

Computation:

Using first equation of motion;

v = u + at

where,

v = final velocity

u = initial velocity

a = acceleration

t = time taken

5.5 = 0 + (1)(t)

5.5 = t

Time taken to reach final velocity = 5.5 second

8 0

2 years ago

Gyroscopic wander can be divided in to two categories, one is DRIFT, what is the other?

Tju [1.3M]

Gyroscopic wander can be divided into two categories and these are:

Drift
Topple

<h3>What is gyroscopic wander?</h3>

Gyroscopic wander can be defined as a movement of the spin axis (axis of rotation) away from a specific fixed direction.

Based on scientific information and records, there are two main types of gyroscopic wander and these include the following:

Drift

Topple

Read more on gyroscopic wander here: brainly.com/question/12168194

#SPJ12

4 0

1 year ago

a force 4000 n accelerates a car of mass 800 kg from rest to 20 ms how far does the car travel while the force is acting?​

a force 4000 n accelerates a car of mass 800 kg from rest to 20 ms how far does the car travel while the force is acting?