Question

a force 4000 n accelerates a car of mass 800 kg from rest to 20 ms how far does the car travel while the force is acting?​

Answer 1

Answer:

d = 40 m

Explanation:

Given that,

Force, F = 4000 N

Mass of a car, m = 800 kg

Initial velocity, u = 0 (at rest)

Final velocity, v = 20 m/s

We need to find the distance traveled. Force acting on a car is given by :

F = ma

Where

a is the acceleration of the car.

$a=\dfrac{F}{m}\\\\a=\dfrac{4000}{800}\\\\a=5\ m/s^2$

Let it has traveled d distance. Using third equation of motion.

$v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{(20)^2-(0)^2}{2\times 5}\\\\d=40\ m$

So, the required distance is equal to 40 m.