a force 4000 n accelerates a car of mass 800 kg from rest to 20 ms how far does the car travel while the force is acting?
1 answer:
Answer:
d = 40 m
Explanation:
Given that,
Force, F = 4000 N
Mass of a car, m = 800 kg
Initial velocity, u = 0 (at rest)
Final velocity, v = 20 m/s
We need to find the distance traveled. Force acting on a car is given by :
F = ma
Where
a is the acceleration of the car.
Let it has traveled d distance. Using third equation of motion.
So, the required distance is equal to 40 m.
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Answer:
v = 719.2 m / s and a = 83.33 m / s²
Explanation:
This is a rocket propulsion system where the system is made up of the rocket plus the ejected mass, where the final velocity is
v - v₀ = ln (M₀ / M)
where v₀ is the initial velocity, v_{e} the velocity of the gases with respect to the rocket and M₀ and M the initial and final masses of the rocket
In this case, if fuel burns at 75 kg / s, we can calculate the fuel burned for the 10 s
m_fuel = 75 10
m_fuel = 750 kg
As the rocket initially had a mass of 3000 kg including 1000 kg of fuel, there are still 250 kg, so the mass of the rocket minus the fuel burned is
M = 3000 -750 = 2250 kg
let's calculate
v - 0 = 2500 ln (3000/2250)
v = 719.2 m / s
To calculate the acceleration, let's use the concept of the rocket thrust, which is the force of the gases on it. In the case of the rocket, it is
Push = v_{e} dM / dt
let's calculate
Push = 2500 75
Push = 187500 N
If we use Newton's second law
F = m a
a = F / m
let's calculate
a = 187500/2250
a = 83.33 m / s²