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Lena [83]
3 years ago
8

Earth is the only planet able to support _____.

Physics
1 answer:
Sergeeva-Olga [200]3 years ago
3 0
<span>Earth is the only planet able to support _____

Life
</span>
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The product of an object’s mass and velocity is its
Alex Ar [27]
The product of an object's mass and velocity is B.momentum.

<span>♡♡Hope I helped!!! :)♡♡
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8 0
3 years ago
Read 2 more answers
Which is true about Pluto
andrew-mc [135]

Answer:

D.)it orbits near the Kepler belt

Explanation:

The Kuiper belt is an area similar to the asteroide belt extending from the orbit of Neptune to about 50 AU from the Sun. It mainly consists of icy asteroids and dwarf planets, which are rocky objects big enough to be defined as planet but that do not have enough gravity to clear their orbit from other obejcts.

Pluto was discovered in 1930 - initially it was classified as a planet, although it is much smaller than the other 8 planets of the Solar System. However, it has been recently de-classified to dwarf planet because its gravity is not enough to clear its orbit from other objects (asteroids). Pluto is located inside the Kuiper belt, so option D is correct. Other dwarf planets in the Kuiper belt are for instance Haumea and Makemake.

8 0
3 years ago
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A circular grill of diameter 0.25 m has an emissivity of 0.8. If the surface temperature is maintained at 150°C, determine the r
Schach [20]

Answer:

the required electrical power when the room air and surroundings are at 30°C.= 52.51822 Watt

Explanation:

Power required to maintain the surface temperature at 150°C from 20°C

P= εσA(T^4-t^4)

P= power in watt

ε= emissivity

A=  area of surface

T= 150°C= 423 K

t= 20°C= 303K

/sigma= 5.67×10^{-8} watt/m^2K^4

putting vales we get

= 0.8\times5.67\times10^{-8} \pi\frac{0.25^4}{4}(423^4-303^4)

P=52.51822 Watt

the required electrical power when the room air and surroundings are at 30°C.= 52.51822 Watt

4 0
3 years ago
One day you are driving your friends around town and you drive quickly around a corner without slowing down. You are going at a
Novay_Z [31]

Answer:

1.60 g

Explanation:

From the attached file below:

we can deduce that:

v =  v_x =v_y = 20 \ m/s \\t = 2s

The distance traveled by 2 s will be:

x = vt

x = 20 m/s × 2 s

x = 40 m

The length is quarter of the circle  with radius r,

so; if 2 πr = 4 x

Then radius (r) will be:

r = \frac{4x}{2 \pi}\\\\r = \frac{4*40}{2 \pi}

r = 25.5 m

The centripetal acceleration can be expressed as:

a = \frac{v^2}{r}

so;

a = \frac{(20 \ m/s^2)}{25.5 \ m}

a = 15.7 m/s²

the magnitude of the acceleration experienced by your unfortunate passengers in terms of acceleration due to gravity is then determined by the equation:

a' = \frac{a}{g} g

a' = \frac{15.7 \m/s ^2}{9.81 \ m/s^2}\ g

a' = 1.60 \ g

∴ The magnitude of the acceleration experienced by your unfortunate passengers during the turn = 1.60 g

6 0
3 years ago
Read 2 more answers
What is atom.......... ?​
aliina [53]

Answer: the basic unit of a chemical element.

Explanation:

An atom is the smallest unit of ordinary matter that forms a chemical element. Every solid, liquid, gas, and plasma is composed of neutral or ionized atoms. Atoms are extremely small, typically around 100 picometers across.

hope this helps

8 0
3 years ago
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