The spring is neither stretched nor compressed. an object having a mass m is attached to the free end of the spring. consider an action
Explanation:
soln,
weight=600N
mass=?
gravity=9.8 m/s²
now,
- mass=weight/gravity
- mass=600/9.8
- mass=61.22kg
hope it helps.
<h2>stay safe healthy and happy.</h2>
<u>Answer</u>
B•Horizontal=11.49 m/s
Vertical=9.64 m/s
Using the concept of a trigonometric ratios,
sin θ = y/hypotenuse
where y is the vertical component.
sin 40 = y/15
y = 15 × sin 40
= 9.64 m/s
vertical component = 9.64 m/s
cos θ = x/hypotenuse
where x is the horizontal component
cos 40 = x/15
x = 15 × cos 15
=11.49
Horizontal component = 11.49 m/s
To find the rate of deceleration, subtract the initial velocity from the final velocity.
Answer:
Part a)
a = -9.81 m/s/s
Part b)
v = 0
Part c)
v = 9.81 m/s
Part d)

Explanation:
Part a)
During the motion of ball it will have only gravitational force on the ball
so here the acceleration of the ball is only due to gravity
so it is given as

Part b)
As we know that ball is moving against the gravity
so here the velocity of ball will keep on decreasing as the ball moves upwards
so at the highest point of the motion of the ball the speed of ball reduce to zero

Part c)
We know that the total time taken by the ball to come back to the initial position is T = 2 s
so in this time displacement of the ball will be zero



Part d)
at the maximum height position we know that the final speed will be zero
so we will have

here we have

