All categories

2 years ago

Volume of 10 coin is 25ml what is the volume of 1 coin

Physics

1 answer:

timama [110]2 years ago

5 0

Answer: 2.5 ML

Explanation:

10 ÷ 10 = 1

25 ÷ 10 = 2.5

The volume of 1 coin is 2.5 ML

You might be interested in

Consider an ideal spring, with spring constant k, which is oriented along an x-axis. one end of the spring is fixed, and the fre

Blizzard [7]

The spring is neither stretched nor compressed. an object having a mass m is attached to the free end of the spring. consider an action

5 0

2 years ago

The weight of a body is 600 N. What is the mass of the body on the surface of the earth?

mamaluj [8]

Explanation:

soln,

weight=600N

mass=?

gravity=9.8 m/s²

now,

mass=weight/gravity
mass=600/9.8
mass=61.22kg

hope it helps.

<h2>stay safe healthy and happy.</h2>

7 0

2 years ago

Read 2 more answers

5-A baseball is hit with a velocity of 15 m/s at an angle of 40° in the horizontal direction. What are the horizontal and vertic

borishaifa [10]

<u>Answer</u>

B•Horizontal=11.49 m/s

Vertical=9.64 m/s

Using the concept of a trigonometric ratios,

sin θ = y/hypotenuse

where y is the vertical component.

sin 40 = y/15

y = 15 × sin 40

= 9.64 m/s

vertical component = 9.64 m/s

cos θ = x/hypotenuse

where x is the horizontal component

cos 40 = x/15

x = 15 × cos 15

=11.49

Horizontal component = 11.49 m/s

5 0

3 years ago

How do you find a rate of deceleration

Irina18 [472]

To find the rate of deceleration, subtract the initial velocity from the final velocity.

4 0

3 years ago

Read 2 more answers

A tennis player tosses a tennis ball straight up and then catches it after 2.00 s at the same height as the point of release. (a

Readme [11.4K]

Answer:

Part a)

a = -9.81 m/s/s

Part b)

v = 0

Part c)

v = 9.81 m/s

Part d)

$H = 4.905 m$

Explanation:

Part a)

During the motion of ball it will have only gravitational force on the ball

so here the acceleration of the ball is only due to gravity

so it is given as

$a = g = 9.81 m/s^2$

Part b)

As we know that ball is moving against the gravity

so here the velocity of ball will keep on decreasing as the ball moves upwards

so at the highest point of the motion of the ball the speed of ball reduce to zero

$v_f = 0$

Part c)

We know that the total time taken by the ball to come back to the initial position is T = 2 s

so in this time displacement of the ball will be zero

$\Delta y = 0 = v_y t + \frac{1}{2} at^2$

$0 = v_y (2) - \frac{1}{2}(9.81)(2^2)$

$v_y = 9.81 m/s$

Part d)

at the maximum height position we know that the final speed will be zero

so we will have

$v_f^2 - v_i^2 = 2 a d$

here we have

$0 - (9.81^2) = 2(-9.81)H$

$H = 4.905 m$

4 0

3 years ago