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Mnenie [13.5K]
3 years ago
10

Volume of 10 coin is 25ml what is the volume of 1 coin

Physics
1 answer:
timama [110]3 years ago
5 0

Answer: 2.5 ML

Explanation:

10 ÷ 10 = 1

25 ÷ 10 = 2.5

The volume of 1 coin is 2.5 ML

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If a cable insulation is described as RHW, you would be able to use the cable for what maximum temperature?
BartSMP [9]
167•F which is c


Tell me my wrong from right
7 0
3 years ago
N in-ground swimming pool has the dimensions shown in the drawing. It is filled with water to a uniform depth of 3.00 m. The den
Doss [256]

Answer:

The pressure is  P = 1.31*10^{5} \ Pa

Explanation:

From the question we are told that

    The depth of the swimming pool is  d =  3.00 \  m

     The density of water is  \rho = 1.00*10^{3} \  kg /m^3

Generally the  total pressure exerted on the bottom of the swimming pool is mathematically represented as

          P = P_o + \rho * g * h

Here P_o is the atmospheric pressure with value

        P_o  =  101325 \  Pa

So

        P = 101325 + [1000 * 9.8 * 3]

=>     P = 130725 \ Pa

=>    P = 1.31*10^{5} \ Pa

     

7 0
3 years ago
A force of 1.00 x 10^2 pounds acts at an angle of 60.0° to the x-axis. (The force is accurate to 3 significant figures.) What ar
tamaranim1 [39]

Answer:

Fx= 50.0 Pounds : Components of the force along the x-axis

Fy= 86.6 Pounds : Component of the force along the y-axis

Explanation:

Conceptual Analysis

To find the components (Fx, Fy) of the total force (F), we apply the trigonometric concepts for a right triangle, where the perpendicular sides of the triangle are the components (Fx, Fy) of the force (F), the hypotenuse (h) is the magnitude of the total force F and β is the angle that forms the horizontal component with the hypotenuse.

Formulas

cos β : x/h  :    x: side adjacent to the β angle  h: hypotenuse  (1)

sin β = y/h  :    y: side opposite to the β angle  h: hypotenuse  (2)

Known Data

Known data

F= 1.00 * 10² pounds  = 100 pounds :  magnitude of total force

β =  60.0° to the x-axis. : Angle that forms the force with the x-axis

Problem Development

We apply the formula 1 to calculate horizontal component (Fx)

cos β :Fx/F

Fx= F cosβ  = 100*cos 60° = 50.0 Pounds

We apply the formula 2 to calculate vertical component (Fy)

sin β = Fy/F

Fy= F sinβ = 100*sin 60° = 86.6 Pounds

6 0
4 years ago
Calculate the amount of work done if you use a 100N force to push a 50kg box 5m across the kitchen floor.
irinina [24]
So if the formula for work is force times displacement times cosine(theta), you'd plug in the numbers

100x5 (since there's no angle in the problem, cosine(theta) isn't used

100x5 = 500

So the answer would be B.

Hope that helps!
6 0
3 years ago
Read 2 more answers
I WILL MARK AS BRAINLIST
puteri [66]

Explanation:

Area=1.5(1.5)=2.25m^2

Force of gravity=10N

\begin{gathered}\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}\end{gathered}

⟼Pressure=

Area

Force

\begin{gathered}\\ \sf\longmapsto Pressure=\dfrac{10}{2.25}\end{gathered}

⟼Pressure=

2.25

10

\begin{gathered}\\ \sf\longmapsto Pressure=4.4Pa\end{gathered}

⟼Pressure=4.4Pa

5 0
3 years ago
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