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Tom [10]
4 years ago
12

You measure a distance of 185 feet. How many meters is this?

Physics
1 answer:
EastWind [94]4 years ago
5 0

-- Take the 185 feet.

-- Multiply it by (12 inches / 1 feet)

-- Multiply it by (2.54 cm / 1 inch)

-- Multiply it by (1 meter / 100 cm)

Doesn't all this multiplying change the value of the 185 feet ?

NO, it doesn't.  Each of those fractions has the exact same thing on top and on the bottom.  So each of those fractions is equal to ' 1 '.  It doesn't change the value of the 185 feet ... it only changes the UNITS.

Length = (185 feet) x (12 inches/1 feet) x (2.54 cm/1 inch) x (1 meter/100 cm)

Length = (185 x 12 x 2.54) / (1 x 1 x 100) (feet-inch-cm-meter / feet-inch-cm)

Length = <em>56.388 meters</em>

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The maximum flame temperature in a fire is 1500-1600K due to radiation and absorption.

<h3>What do you mean by radiation and absorption?</h3>

In physics, matter (usually electrons bound in atoms) absorbs electromagnetic radiation in order to convert the energy of a photon into the internal energy of the absorber (for example, thermal energy). Attenuation, or the steady decrease in light wave intensity as it travels through a medium, is a prominent effect. In some circumstances (optics), the medium's transparency changes by a factor that varies as a function of wave intensity, leading to saturable absorption (or nonlinear absorption), even though the absorption of waves typically does not depend on their intensity (linear absorption).

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A 150-kg object takes 1.5 minutes to travel a 2,500- meter straight path. It begins the trip traveling 120 m/s and decelerates t
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4 0
3 years ago
A disk of radius a has a total charge Q uniformly distributed over its surface. The disk has negligible thickness and lies in th
sleet_krkn [62]

The electric potential V(z) on the z-axis is :  V = (\frac{Q}{a^2} ) [ (a^2 + z^2)^{\frac{1}{2} } -z

The magnitude of the electric field on the z axis is : E = kб 2\pi( 1 - [z / √(z² + a² ) ] )

<u>Given data :</u>

V(z) =2kQ / a²(v(a² + z²) ) -z  

<h3>Determine the electric potential V(z) on the z axis and magnitude of the electric field</h3>

Considering a disk with radius R

Charge = dq

Also the distance from the edge to the point on the z-axis = √ [R² + z²].

The surface charge density of the disk ( б ) = dq / dA

Small element charge dq =  б( 2πR ) dr

dV  \frac{k.dq}{\sqrt{R^2+z^2} } \\\\= \frac{k(\alpha (2\pi R)dR}{\sqrt{R^2+z^2} }  ----- ( 1 )

Integrating equation ( 1 ) over for full radius of a

∫dv = \int\limits^a_o {\frac{k(\alpha (2\pi R)dR)}{\sqrt{R^2+z^2} } } \,

 V = \pi k\alpha [ (a^2+z^2)^\frac{1}{2} -z ]

     = \pi k (\frac{Q}{\pi \alpha ^2})[(a^2 +z^2)^{\frac{1}{2} }  -z ]

Therefore the electric potential V(z) = (\frac{Q}{a^2} ) [ (a^2 + z^2)^{\frac{1}{2} } -z

Also

The magnitude of the electric field on the z axis is : E = kб 2\pi( 1 - [z / √(z² + a² ) ] )

Hence we can conclude that the answers to your question are as listed above.

Learn more about electric potential : brainly.com/question/25923373

7 0
3 years ago
Insulators are materials that reduce heat flow. Nature uses many types of insulation to protect animals from losing too much hea
katrin2010 [14]

Answer:

This has all the answer (Data sheet, graph, answers to the questions, and the summary) :)

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