Answer:
Explanation:
A pressure that causes the Hg column to rise 1 millimeter is called a torr. The term 1 mmHg used can replaced by the torr.
1 atm = 760 torr = 14.7 psi.
A.
120 mmHg
Psi:
760 mmHg = 14.7 psi
120 mmHg = 14.7/760 * 120
= 2.32 psi
Pa:
1mmHg = 133.322 Pa
120 mmHg = 120 * 133.322
= 15998.4 Pa
B.
80 mmHg
Psi:
760 mmHg = 14.7 psi
80 mmHg = 14.7/760 * 80
= 1.55 psi
Pa:
1mmHg = 133.322 Pa
80 mmHg = 80 * 133.322
= 10665.6 Pa
Answer:
4 seconds
Explanation:
The frequency of a body is the number of oscillations in one second. It is the number of cycles per unit time. The S.I unit of frequency is the Hertz (Hz).
The period of a body is the time taken to complete one oscillation. The period is inversely proportional to the frequency of the body. It is the reciprocal of frequency and the S.I unit is second (s).
A body oscillates with 25hz. Therefore the frequency (f) = 25 Hz.
The period (T) is given as:
At theheight where it starts, just before it's dropped, the ball has
some potential energy. The higher that spot is, the more potential
energy the ball has. After the drop, whenever the ball is lower than
the height from which it was dropped, it has less potential energy, and
the missing potential energy shows up as kinetic energy ... motion.
This is the whole idea of the roller coaster. A machine drags it up to
the top of the first hill, giving it lots of potential energy. After that, as
long as it doesn't try to rise higher than the first hill, it never runs out
of energy, and keeps going.
A). and B).
The ball keeps going forward until it rises again to the same height it
was dropped from ... on the other side. Then it stops and falls back.
C). The ball can never rise higher than the height it was dropped from.
If the hump in the middle is the same height as the drop-height, then
the ball stops right there, and falls back.
D). Same as B). As long as the track inside the loop is never higher
than the droop-height, the ball just keeps going forward.
E). Same idea. Here it looks like the drop-height is the same as the
top of the loop. The ball can't rise higher than it was dropped from,
so it gets as far as the top of the loop and stops there. From there,
I think it drops straight down from the top of the loop, instead of
following the curve.
Sadly, no. The statement kind of has some appropriate words in it, but it's badly corrupted. Objects don't fall to Earth at a rate of 9.8 m/s, and the force that accelerates them downward is not a centripetal one.
Answer:
Explanation:
average deceleration= ?
inial velocity: 
final velocity: 
time: 
The first law of kinematics :
find a the subject of the formula
The deceleration about g(acceleration due to gravity) will be:
