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miss Akunina [59]
3 years ago
9

Two technicians are discussing how a clutch disengages. Technician A says a gap on each side of the clutch disk facing when dise

ngaged. Technician B says the marcel/cushion plage in the disc will flatten. Who is Correct?
Physics
2 answers:
victus00 [196]3 years ago
5 0

Answer: A - a gap on each side of the clutch disk facing when disengaged

Explanation:

A clutch switch is used to ensure the clutch is disengaged

or Prevent the engine from starting unless the clutch pedal is depressed

When a clutch is disengageda gap will be on each side of the facing.

AURORKA [14]3 years ago
5 0

Answer:

<em>Technician A is correct</em>

Explanation:

<em>A clutch switch is used in preventing  an  engine from starting unless the pedal of the clutch  is depressed  or to ensure the clutch  totally disengaged  .</em>

<em> The clutch switch is located normally underneath the dash, while i is still in gear it stops  you from starting a vehicle to start . The clutch switch is activated by the clutch pedal arm when the clutch is pushed down and also  attached to the pedal linkage.</em>

<em>From the question given, Technician A is right.</em>

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A 60-kg skate boarder is standing on his stationary board. A bigger, out of control 75-kg skate boarder crashes into him with a
andrezito [222]

Answer:

2.22m/s

Explanation:

Given parameters:

M1  = 60kg

M2  = 75kg

V1  = 0m/s

V2  = 4m/s

Unknown;

Velocity after collision  = ?

Solution:

To solve this problem, we must understand that the momentum before and after collision of the bodies must be the same;

     M1 V1  + M2 V2  = v(M1 + M2)

So;

       60 x 0  +  75 x 4  = v (60 +75)

                 300  = 135v

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3 0
3 years ago
The amount of the lighted side of the moon you can see is the same during
attashe74 [19]

<u>Answer:</u>

The amount of the lighted side of the moon you can see is the same during "how much of the sunlit side of the moon faces Earth".

<u>Explanation:</u>

The Moon is in sequential rotation with Earth, and thus displays the Sun, the close side, always on the same side. Thanks to libration, Earth can display slightly greater than half (nearly 59 per cent) of the entire lunar surface.

The side of the Moon facing Earth is considered the near side, and the far side is called the reverse. The far side is often referred to as the "dark side" inaccurately but it is actually highlighted as often as the near side: once every 29.5 Earth days. During the New Moon the near side becomes blurred.

5 0
3 years ago
You stand on a straight desert road at night and observe a vehicle approaching. This vehicle is equipped with two small headligh
g100num [7]

To solve this problem we will apply trigonometric and optical concepts that allow us to obtain the minimum distance required. The resolution of the eye is given under the following condition,

\theta = \frac{1.22\lambda}{D}

Here,

\lambda = Wavelength

D = Diameter

With the values we have that the diameter will be,

\theta = \frac{1.22(534nm)}{5.37mm}

\theta = 1.213*10^{-4}

The relation between the distance of the lights and the distance from the eye to the lamp is given under the function,

sin\theta = \frac{d}{L}

For small angles sin\theta = \theta, then

\theta = \frac{d}{L}

Here,

d = Distance between lights

L = Distance from eye to lamp

1.213*10^{-4} = \frac{0.673m}{L}

L = \frac{0.673m}{1.213*10^{-4}}

L = 5548.22m

Therefore the distance will be 5.5km

5 0
3 years ago
What would the speed of this wave be?
valentinak56 [21]

Answer:

c) 100,000 m/s

Explanation:

You need to take the same wave length from the top graph and bottom one, so let's take half a wave length then in the top one that is 0.005, but in the bottom one it's 2000/4 = 500 because they are smaller and there are 4 half waves before you get to 2000, whereas in the top one there is 1 half wave before you get to 0.005 on the graph.

Now use speed = distance / time

speed = 500 / 0.005 = 100 000 m/s

7 0
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NikAS [45]

Answer:

3: force acting on an object over time

Explanation:

The impulse formula is: change in momentum = force x time

Δp = f x t

3 0
3 years ago
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