3x - 5y = 7
2x + 3y = 11
multiply the first equation by 2 and the second by -3:-
6x - 10y = 14
-6x - 9y = -33 Adding these 2 equations we eliminate the term in x:-
-19y = -19
y = 1
Substtute y = 1 in the first equation:_
3x - 5(1) = 7
3x = 12
x = 4
Answer is x=4,y=1 Answer
Second system of equation:-s
Here one equation is linear and the other is quadratic so we substitute fro y in the quadratic:-
From second equation y = 10x - 38, so substituting:-
10x - 38 = x^2 - 4x - 17
Gotta go right now . Sorry
So this is how I would do it
4(6)+5
20+5
25
But I could be wrong.
Answer:
C
Step-by-step explanation:
I did the math
I want to say D, but don't take my word for it. Good luck! <3
So i just finished this lesson. I am taking Algebra 1.
All you need to do is determine which number is X, and which number is Y. The formula is Y2-Y1 over X2-X1. Here is an example. And then make sure you simplify it to simplest form.