Answer:
The amount of acid in third container is =42%
Step-by-step explanation:
Given , one container is filled with a mixture that is 30% acid a second container filled with a mixture that is 50% acid and the second container 50% larger than the first .
Let, the volume of first container is = x
Then , the volume of second container = (x+ x of 50%)
= x + 0.5 x
= 1.5 x
Therefore the amount of acid in first container
= 0.3 x
The amount of acid in second container
= 0.75x
Total amount of acid= 0.3x + 0.75x = 1.05 x
Total amount of solution = x+1.5x = 2.5x
The amount of acid in third container is =
%
= 42%
102/159 = x/4
34/53 = x/4
34(4) = x(53)
136 = 53x
136/53 = x
Answer:
A and D
Step-by-step explanation:
4×3=12
4×d=4d
12+4d
Then;(4×d)+(3×4)=4d +12
Same expression
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