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Goshia [24]
3 years ago
14

(0 - -3) x (1 + 5) divided by ( 2 - -2)

Mathematics
2 answers:
ElenaW [278]3 years ago
4 0

Answer:

4.5

hope it's helpful ❤❤❤❤❤❤

THANK YOU.

Amiraneli [1.4K]3 years ago
3 0

Answer:

4.5

Step-by-step explanation:

(0-(-3))x(1+5) divided by (2 -(-2))

When adding or subtracting 0, the quantity does not change

-(-3)x(1+5) / (2-(-2))

When there is a - in front of an expression in parentheses, change the sign of each term in the expression

3(1+5) / (2-(-2))

Add the numbers

3x6 / (2-(-2))

When there is a - in front of an expression in parentheses, change the sign of each term in the expression

3x6 / (2+2)

Add the numbers

3x6 / 4

Calculate the expression

=4.5

Alternative Form= 9/2, 4 1/2

if you could give me brainliest that'd be amazing! if not thats alright too, hope this helps!!

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In a sample of nequals16 lichen​ specimens, the researchers found the mean and standard deviation of the amount of the radioacti
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Answer:

(a) The confidence level desired by the researchers is 95%.

(b) The sampling error is 0.002 microcurie per millilitre.

(c) The sample size necessary to obtain the desired estimate is 25.

Step-by-step explanation:

The mean and standard deviation of the amount of the radioactive​ element, cesium-137 present in a sample of <em>n</em> = 16 lichen specimen are:

\bar x=0.009\\s=0.005

Now it is provided that the researchers want to increase the sample size in order to estimate the mean μ to within 0.002 microcurie per millilitre of its true​ value, using a​ 95% confidence interval.

The (1 - <em>α</em>)% confidence interval for population mean (μ) is:

CI=\bar x\pm z_{\alpha/2}\times \frac{s}{\sqrt{n}}

(a)

The confidence level is the probability that a particular value of the parameter under study falls within a specific interval of values.

In this case the researches wants to estimate the mean using the 95% confidence interval.

Thus, the confidence level desired by the researchers is 95%.

(b)

In case of statistical analysis, during the computation of a certain statistic, to estimate the value of the parameter under study, certain error occurs which are known as the sampling error.

In case of the estimate of parameter using a confidence interval the sampling error is known as the margin of error.

In this case the margin of error is 0.002 microcurie per millilitre.

(c)

The margin of error is computed using the formula:

MOE=z_{\alpha/2}\times \frac{s}{\sqrt{n}}

The critical value of <em>z</em> for 95% confidence level is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use a <em>z</em>-table.

MOE=z_{\alpha/2}\times \frac{s}{\sqrt{n}}

 0.002=1.96\times \frac{0.005}{\sqrt{n}}

       n=[\frac{1.96\times 0.005}{0.002}]^{2}

          =(4.9)^{2}\\=24.01\\\approx 25

Thus, the sample size necessary to obtain the desired estimate is 25.

6 0
4 years ago
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