Explanation:
Given parameters:
Jermaine runs exactly 2 laps around a 400m track
Start time = 3:02:00PM
End time = 3:04:45PM
Unknown:
Distance traveled = ?
Speed = ?
Displacement = ?
Velocity = ?
Solution:
To solve this problem, we need to find the distance and time first;
Distance = 2 x 400 = 800m
Time taken = 3:04:45PM - 3:02:00PM = 165s
Speed = = = 4.85m/s
The velocity of the body is 0m/s and so is the displacement.
This is because the starting and finishing position of the Jermaine is the same.
When the key is off there should be no current in the circuit.
Our ammeter still measures some current, and this is called hysteresis error. This means that this particular ammeter is going to add some amount of current to any current measured. In order to compensate for this error, we simply we deduct it from all measurements.
Each mark on the ammeter is worth:
This means that our error is:
When the circuit is closed we measure:
This is current with the error, real current in the circuit is:
Answer:
An electric current passing through a coil of wire gives a strong form of magnetism called electromagnetism. When the electric current passes through a single straight piece of wire the electromagnetism is weak.
Explanation:
Assume this is 22 degrees from the horizontal (x).
A vector can always be split into components - in this case we can think of the world in two dimensions, meaning the 72ms-1 has a vertical and a horizontal component. We therefore know the hypotenuse of the triangle (the overall velocity) and the angle from the ground. Hence we can use trigonometry to solve this problem.
We know x and the hypotenuse, and we want to know the magnitude of the adjacent side (horizontal), therefore we can use cosx=adj/hyp
Substituting:
Cos(22) = adj/72
Adj = 72cos22 = 66.8ms-1 = 67ms-1 to 2sf
The harmonic frequency of a musical instrument is the minimum frequency at which a string that is fixed at both ends in the instrument may vibrate. The harmonic frequency is known as the first harmonic. Each subsequent harmonic has a frequency equal to:
n*f, where n is the number of the harmonic and f is the harmonic frequency. Therefore, the harmonic frequency may be calculated using:
f = 100 / 2
f = 50 Hz