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Vitek1552 [10]
3 years ago
14

the attendance qt a seminar in a year 1 was 500 in year 2 the attendance changed by 100 what was the percent change in attendanc

e?
Physics
1 answer:
TiliK225 [7]3 years ago
5 0
20% change from year one to year two.
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Which is the correctly balanced equation for the reaction of rust, Fe2O3, and hydrochloric acid, HCl?
Mariana [72]

Answer: Option (c) is correct answer.

Explanation:

The given reaction equation is as follows.

          Fe_{2}O_{3} + HCl \rightarrow FeCl_{3} + H_{2}O

The number of atoms on reactant side are as follows.

  • Fe = 2
  • O = 3
  • H = 1
  • Cl = 1

The number of atoms on product side are as follows.

  • Fe = 1
  • O = 1
  • H = 2
  • Cl = 3

Therefore, in order to balance the equation we will balance the number of atoms in both reactant and product side.

Since number of Fe atoms in reactant side is 2, therefore, multiply FeCl_{3} by 2 in the product side.

Number of O atoms in reactant side is 3, therefore, multiply H_{2}O by 3 in the product side.

Now, the number of H atoms on product side is 6, therefore, multiply HCl by 6 in the reactant side.

The number of chlorine atoms on both reactant and product side equals 6.

Thus, the equation will become as follows.

             Fe_{2}O_{3} + 6HCl \rightarrow 2FeCl_{3} + 3H_{2}O

Hence, the equation is balanced.

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3 years ago
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vladimir2022 [97]

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3 years ago
Choose all the answers that apply.
Serhud [2]
<span>According to Newton's first law of motion:

-- objects at rest will remain at rest unless acted upon by an outside force

-- objects in motion will remain in motion unless acted upon by an outside force


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8 0
3 years ago
An object is thrown 16m/s straight up from a 7m tall cliff. How much time does it take to hit the ground below
harkovskaia [24]

Answer:

0,54 sec

Explanation:

t=s/v

t=7/13 s=0,54sec

5 0
3 years ago
A man starts from rest and accelerates at 4.00 m/s2. If he covers a distance of 525 m, how long does he accelerate?
rosijanka [135]

Answer:

16.2 s

Explanation:

Given:

Δx = 525 m

v₀ = 0 m/s

a = 4.00 m/s²

Find: t

Δx = v₀ t + ½ at²

525 m = (0 m/s) t + ½ (4.00 m/s²) t²

t = 16.2 s

5 0
3 years ago
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