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Akimi4 [234]
3 years ago
6

9. What is the coefficient of y^2? in the expansion of (x + y)^2??

Mathematics
1 answer:
klemol [59]3 years ago
3 0

Answer:

The coefficient of y² will be 1, which we can see when we expand the expression:

(x + y)²

= (x +y)(x + y)

= x² + xy + xy + y²

= x² + 2xy + y²

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Ejercicio1:
Lemur [1.5K]

Answer:

Cost of car including VAT = $17,700

Step-by-step explanation:

Given:

Cost of car without VAT = $15,000

Rate of VAT = 18%

Find:

Cost of car including VAT

Computation:

Cost of VAT = Cost of car without VAT x Rate of VAT

Cost of VAT = 15,000 x 18%

Cost of VAT =  15,000 x 18

Cost of VAT = $2,700

Cost of car including VAT = Cost of car without VAT + Cost of VAT

Cost of car including VAT = 15.000 + 2700

Cost of car including VAT = $17,700

5 0
3 years ago
What is the equation of the line that passes through the point (2,0) and has a slope<br> of 5/2
andrezito [222]

Answer:

y = 5/2x - 5

Step-by-step explanation:

Please let me know if you want me to add an explanation as to why this is the answer/how I got this answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)

3 0
3 years ago
Given the function f(x) = x3 + x2 − 2x + 1, what is the resulting function when f(x) is shifted to the left 1 unit?
Mekhanik [1.2K]
The answer is B.

Explanation:

If c is a positive real number, then the graph of
f(x – c) is the graph of y = f(x) shifted to the right
c units.
Horizontal Shifts
If c is a positive real
number, then the
graph of f(x + c) is
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8 0
4 years ago
Read 2 more answers
Elizabeth attempts a field goal by kicking a football from the ground with an initial vertical
sammy [17]

\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{64}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{0\qquad \textit{from the ground}}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf h(t)=-16t^2+64t+0\implies h(t)=-16t^2+64t\implies \stackrel{\textit{hits the ground}~\hfill }{0=-16t^2+64t} \\\\\\ 0=-16t(t-4)\implies t= \begin{cases} 0\\ \boxed{4} \end{cases}

Check the picture below, it hits the ground at 0 feet, where it came from, the ground, and when it came back down.

5 0
3 years ago
What which relationship in each of the following represents a Non-proportional relationship
sergij07 [2.7K]
The answer is C y =3.5x
6 0
3 years ago
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