Question

The angle of elevation of the top of the tower from a point on the ground is 30 degree, If the height of the tower is 40 space m e t e r s, then the distance between the tower and the point is​

Answer 1

Answer:

$40\sqrt3\ m$

Step-by-step explanation:

Given that,

The height of the tower, h = 40 m

The angle of elevation is 30°

We need to find the distance between the tower and the point. Let the distance is x. Using trigonometry,

$\tan(30)=\dfrac{h}{x}\\\\\dfrac{1}{\sqrt3}=\dfrac{40}{x}\\\\x=40\sqrt3\ m$

So, the distance between the tower and the point is equal to $40\sqrt3\ m$.