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3 years ago

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The angle of elevation of the top of the tower from a point on the ground is 30 degree, If the height of the tower is 40 space m

e t e r s, then the distance between the tower and the point is

1 answer:

kiruha [24]3 years ago

7 0

Answer:

$40\sqrt3\ m$

Step-by-step explanation:

Given that,

The height of the tower, h = 40 m

The angle of elevation is 30°

We need to find the distance between the tower and the point. Let the distance is x. Using trigonometry,

$\tan(30)=\dfrac{h}{x}\\\\\dfrac{1}{\sqrt3}=\dfrac{40}{x}\\\\x=40\sqrt3\ m$

So, the distance between the tower and the point is equal to $40\sqrt3\ m$ .

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