Describe what a geologist would observe if she poured acid on the sculpture

Chemistry

1 answer:

natita [175]2 years ago

6 0

Answer:

A geologist would observe how the material that the sculpture is made out of reacts to the acid.

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3) Explain the difference between CO2 and C204.

kkurt [141]

Answer:

CO2 consists of one carbon atom and 2 oxygen atoms, where as C2O4 consists of 2 carbon atoms and 4 oxygen atoms. CO2 has a ration of one carbon atom to every 2 oxygen atoms and C2O4 has a ratio of 1:2 aswell

Explanation:

5 0

3 years ago

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What substance would you add to KF(aq) to form a buffer solution? View Available Hint(s) What substance would you add to to form

AnnyKZ [126]

<h3>Answer</h3>

<h3>Explanation</h3>

A buffer solution contains <em>a weak acid</em> and<em> its conjugate base</em>. The two species shall have a similar concentration in the solution. It's also possible for <em>a weak base</em> and <em>its conjugate acid</em> to form a buffer solution.

The KF solution already contains large number of $\text{F}^{-}$ ions. The objective is to thus find its conjugate acid or base.

$\text{F}^{-}$ contains no proton $\text{H}^{+}$ and is unlikely to be a conjugate acid. Assuming that $\text{F}^{-}$ is a conjugate base. Adding one proton to $\text{F}^{-}$ would produce its conjugate acid.

$\text{H}^{+} \; (aq) + \text{F}^{-} \; (aq) \rightleftharpoons \text{HF}\; (aq)$

Therefore $\text{HF}$ is the conjugate acid of $\text{F}^{-}$ . $\text{HF}$ happens to be a weak acid. As a result, combining $\text{F}^{-}$ with $\text{HF}$ would produce a solution with large number of both the weak acid and its conjugate base, which is a buffer solution by definition.

4 0

3 years ago

The same amount of heat is removed from 2kg of water and from 1kg of water starting at the same temperature. What happen?

Luda [366]

The temperature of the 1 kg water will be lower.
Q=mcΔt
Q1= 1kg*c*Δt(1)
Q2= 2kg*c*Δt(2)

Q1=Q2
1kg*c*Δt(1) = 2kg*c*Δt(2)
Δt(1) = 2Δt(2)
We can see that change in temperature for 1 kg will be 2 times more that change in temperature for 2 kg of water.

5 0

3 years ago

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What is the mass of 24.6 cm3 of gasoline (density 0.680 g/cm3)?

Nata [24]

Answer:

$density = \frac{mass}{volume} \\ \: mass = density \times volume \\ mass = 0.680 \frac{g}{ {cm}^{3} } \times 24.9 {cm}^{3} \\ = 16.728g$