Answer:
The molality ( m ) of a solution is the moles of solute divided by the kilograms of solvent. A solution that contains 1.0 mol of NaCl dissolved into 1.0 kg of water is a “one-molal” solution of sodium chloride. The symbol for molality is a lower-case m written in italics.
In order to calculate the molality of a solution divide the moles of solute by the volume of the solution expressed in liters.
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<span>On the periodic table, the majority of elements are classified as "Metals"
In short, Your Answer would be Option A
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Answer:
2 moles
Explanation:
The following were obtained from the question:
Molarity = 0.25 M
Volume = 8L
Mole =?
Molarity is simply defined as the mole of solute per unit litre of solution. It is represented mathematically as:
Molarity = mole of solute/Volume of solution.
With the above equation, we can easily find the number of mole of MgCl2 present in 8 L of 0.25 M MgCl2 solution as follow:
Molarity = mole of solute/Volume of solution.
0.25 = mole of MgCl2 /8
Cross multiply to express in linear form
Mole of MgCl2 = 0.25 x 8
Mole of MgCl2 = 2 moles
Therefore, 2 moles of MgCl2 are present in 8 L of 0.25 M MgCl2 solution
The following Balanced Reaction will take place:
Zn + 2HCl → ZnCl₂ + H₂
In the question, we have 2 moles of Zinc and 3 moles of HCl for this reaction
<u>Amount of HCl required to completely react with 2 moles of Zn:</u>
Since we need 2 moles of HCl for every mole of Zn, we will need 2(2) = 4 moles of HCl for every 2 moles of Zn
<u>Identifying the Limiting Reagent:</u>
But we are only given 3 moles of HCl where we need 4 moles to completely react.
So, since HCl is in less amount, it is the Limiting Reagent
