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antiseptic1488 [7]
2 years ago
7

What does Fe(NO3)2 + Cu stands for?​

Chemistry
1 answer:
Gwar [14]2 years ago
7 0
Copper nitrate

Copper nitrate is the oxidizing agent as it gets reduced from +2 to 0 oxidization State and oxidize Fe from 0 to +2 state.
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krok68 [10]
Super giants have the greatest luminosity!
8 0
2 years ago
PLEASE HELP!!! Which type of substance is gold an example of?
dmitriy555 [2]

Answer:

Hello!

Gold is a chemical element with symbol Au (from Latin: aurum) and atomic number 79. In its purest form, it is a bright, slightly reddish yellow, dense, soft, malleable, and ductile metal. Chemically, gold is a transition metal and a group 11 element.

So in short, the Correct Answer will be (D) an Element.

Hope that Helps! Have A Wonderful Day! ☺

Explanation:

7 0
2 years ago
Read 2 more answers
!!HELP PLS!! A compound sample contains 0.783g of C, 0.196 g of H, 0.521 g 0 and the molecular formula molar mass is 184.27g/mol
Delvig [45]

Answer:

First

divide each element by its Molecular Mass to get their respective moles

Then Divide through by the lowest of the moles

You'll have the ratio of Carbon Hydrogen and Oxygen to be

C2H3O

Given Molecular Mass=184.27

C2H3On=184.27

n(12x2 + 1x3 + 16) =184.27

Evaluating this... You'll have n=4.3

Pls check if you assigned the correct value to each element

4 0
2 years ago
For the chemical reaction:
Kamila [148]

Answer:

Volume of ammonia produced = 398.7 dm³

Explanation:

Given data:

Volume of N₂ = 200 dm³

Pressure and temperature = standard

Volume of ammonia produced = ?

Solution:

Chemical equation:

N₂ + 3H₂     →      2NH₃

Number of moles of N₂:

PV = nRT

1 atm× 200 L = n× 0.0821 atm.L/mol.K × 273 K

n = 200 atm.L /22.41 atm.L/mol

n = 8.9 mol

Now we will compare the moles of ammonia and nitrogen.

               N₂          :         NH₃

                1            :           2

              8.9          :        2/1×8.9 = 17.8 mol

Volume of ammonia:

1 mole of any gas occupy 22.4 dm³ volume

17.8 mol ×22.4 dm³/1 mol = 398.7 dm³

7 0
3 years ago
6. A. If 4.50 mols of ethane, C2H6, undergoes combustion according to the unbalanced equation
uranmaximum [27]

Answer:

for one mole of C2H6 there are 7/2 mole of O2 required. so for4. 50 moles you require 4.50 x 7/2 = 15.75 moles of O2.

Explanation:

i hope it's helpful

6 0
2 years ago
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