Answer:
The third answer option is correct. sqrt(x) = x^(1/2). So sqrt(121) = 121^(1/2)
Answer: 
Step-by-step explanation:
According to the information given in the exercise, you know that:
of the group's video games is at Jerome's house.
of the group's video games is at Mario's house.
Then, you need to add those fractions in order to solve the exercise.
Notice that the denominators of the fractions are different; so in this case, you need to multiply them in order to find the Least Common Denominator (LCD). This is:
Now, the procedure is:
1- Divide each original denominator by the LCD and multiply the numerators by the quotient obtained.
2- Add the products (This sum will be the numerator).
Then, you get the following result:
Answer for problem 46 is choice A
Answer for problem 47 is choice B
Answer for problem 48 is choice E
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Work Shown
Problem 46
Equation 1: 3x+y = 17
Equation 2: x+3y = -1
Add equation 1 to equation 2 to get 4x+4y = 16. Divide every term by 4 to get x+y = 4. Then finally multiply both sides by 3 to get 3x+3y = 12
That shows why the answer is choice A
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Problem 47)
If y hours pass by, then y-(2/3)y=y/3 is the time value (2/3)y hours ago
So,
Distance = rate*time
d = r*t
d = x*(y/3)
d = (xy)/3
That's why the answer is choice B
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Problem 48)
Let L1,L2,L3 be the three lists where
L1 = {a1,a2,a3,...,ak} there are k scores here
L2 = {a1,a2,...,a10} there are 10 scores here
L3 = {a11,a12,...,ak} the remaining k-10 scores
S(L1) = sum of the scores in list L1
M(L1) = mean of L1 = 20 = S(L1)/k
M(L2) = mean of L2 = 15 = S(L2)/10
S(L1) = 20k
S(L2) = 150
S(L1) = S(L2)+S(L3)
M(L1) = [S(L2)+S(L3)]/k
20 = [150+S(L3)]/k
20k = 150+S(L3)
S(L3) = 20k-150
M(L3) = [S(L3)]/(k-10)
M(L3) = (20k-150)/(k-10)
So that shows why the answer is choice E
Answer:
92 are the value of x I think
Only te 1st one (1057), since it's a multiple of 7 (151 x 7 = 1057)
