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Orlov [11]
2 years ago
7

Helpppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppp

Mathematics
2 answers:
kolbaska11 [484]2 years ago
7 0

Answer:

9 baskets             (Do you have a gacha channel?)

Step-by-step explanation:

348/39= around 9 baskets

allochka39001 [22]2 years ago
4 0
You need about 9 baskets
You might be interested in
? x (3 + 2) = 12 + 8 What's the number that goes into the question mark?​
andrew11 [14]

Answer:

?=4

Step-by-step explanation:

?*(3+2)=12+8

?(5)=20

20/5=4

?=4

4*(5)=20

20=20

7 0
2 years ago
Read 2 more answers
If segment UV is considered to be the base of parallelogram TUVW, which segment would represent the altitude of the parallelogra
omeli [17]
The best and most correct answer among the choices provided by your question is the second choice or letter B.

<span>Segment TX is the segment that would best represent the altitude of the parallelogram.</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
5 0
3 years ago
Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y
ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; (x^2-4)^2y'' + (x + 2)y' + 7y = 0

The above equation can be better expressed as:

y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

p(x) = \dfrac{(x+2)}{(x^2-4)^2} \

p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \

p(x) = \dfrac{1}{(x+2)(x-2)^2}

Also;

q(x) = \dfrac{7}{(x^2-4)^2}

q(x) = \dfrac{7}{(x+2)^2(x-2)^2}

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

\lim \limits_{x \to-2} (x+ 2) p(x) =  \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{1}{(x-2)^2}

\implies \dfrac{1}{16}

\lim \limits_{x \to-2} (x+ 2)^2 q(x) =  \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{7}{(x-2)^2}

\implies \dfrac{7}{16}

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

5 0
3 years ago
Question Help
Lady bird [3.3K]

Answer:

19 1-point shots and 32 2-point shots

Step-by-step explanation:

Let x be the amount of 1-point shots they made and y be the amount of 2-point shots they made then...

x+y=51

x+2y=83

We can solve this equation using elimination. In this case, we can eliminate x be subtracting the two equations.

-y=-32

Divide both sides by -1

y=32

Plug this back into the equation to solve for x

x+32=51

Subtract 32 from both sides

x=19

They scored 19 1-point shots and 32 2-point shots.

8 0
2 years ago
HELP ASAP!!!!!!!!!!!
mario62 [17]

Answer:

I can't see the picture

Step-by-step explanation:

8 0
2 years ago
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